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Marta_Voda [28]

3 years ago

7

You have 0.5 l of air at 203 k in an expandable container at constant pressure. you heat the container to 273 k. what is the new

volume?

1 answer:

Leviafan [203]3 years ago

5 0

0.593 L. V1/T1 = V2/T2

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The Haber Process synthesizes ammonia at elevated temperatures and pressures. Suppose you combine 1580 L of nitrogen gas and 351

ikadub [295]

Answer : The volume of reactant measured at STP left over is 409.9 L

Explanation :

First we have to calculate the moles of $N_2$ and $H_2$ by using ideal gas equation.

<u>For $N_2$ :</u>

$PV_{N_2}=n_{N_2}RT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of $N_2$ gas = 1580 L

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times 1580L=n_{N_2}\times (0.0821L.atm/mol.K)\times 273K$

$n_{N_2}=70.49mole$

<u>For $H_2$ :</u>

$PV_{H_2}=n_{H_2}RT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of $H_2$ gas = 3510 L

n = number of moles $H_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times 3510L=n_{H_2}\times (0.0821L.atm/mol.K)\times 273K$

$n_{H_2}=156.6mole$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the balanced reaction we conclude that

As, 3 mole of $H_2$ react with 1 mole of $N_2$

So, 156.6 moles of $H_2$ react with $\frac{156.6}{3}\times 1=52.2$ moles of $N_2$

From this we conclude that, $N_2$ is an excess reagent because the given moles are greater than the required moles and $H_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the excess moles of $N_2$ reactant (unreacted gas).

Excess moles of $N_2$ reactant = 70.49 - 52.2 = 18.29 moles

Now we have to calculate the volume of reactant, measured at STP, is left over.

$PV=nRT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of gas = ?

n = number of moles of unreacted gas = 18.29 moles

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times V=18.29mole\times (0.0821L.atm/mol.K)\times 273K$

$V=409.9L$

Therefore, the volume of reactant measured at STP left over is 409.9 L

8 0

3 years ago

what is the total ionic and net ionic equation for for the reaction between between mercury (II) nitrate and iron (III) chloride

MArishka [77]

Answer:

Hg+2 + 2Cl- -> HgCl2

HOPE THIS HELPS HAVE A GREAT DAY/NIGHT!!~

Explanation:

7 0

2 years ago

Calculate the molarity of 0.289 moles of FeC13 dissolved in 120 ml of solution

yanalaym [24]

Answer:

2.41 M

Explanation:

The molarity is the moles of FeCl3 over the liters of solution. Since you're given mL you need to change it to L which is 0.12 L. 0.289 divided by 0.12 is your answer

5 0

3 years ago

Through which of the following ways can heat be transferred?

SashulF [63]

Answer:

The correct option is:

A) by direct or indirect contact between objects at different temperatures

Explanation:

Heat can be transferred in three different methods:

Conduction, Convection and Radiation

Conduction is heat transfer through direct contact between substances at different temperatures.

Convection is the heat transfer which takes place through air currents.

Radiation is the heat transfer that does not require contact between two objects.

Hence, heat transfer can take place through direct or indirect contact between objects at different temperatures.

4 0

3 years ago

Place each phases of the moon in the correct order, starting with the new moon

9966 [12]

New moon, crescent moon, first quarter moon, gibbous moon, full moon.
Hope this Helps! :)

8 0

3 years ago