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slamgirl [31]
3 years ago
6

To raise an arm upward, the muscle on one side of it contracts. What happens to the muscle on the opposite side of the arm?

Physics
2 answers:
s2008m [1.1K]3 years ago
6 0

Answer:

it relaxes B

Explanation:

enyata [817]3 years ago
5 0

Answer:

It relaxes

Explanation:

I took the test I hope it helps

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A ball tied on a string rotates in a circular path as shown above. The only forces acting on the ball at any point are the weigh
Harlamova29_29 [7]

Answer:

the third one T-W

Explanation:

the direction of the Tension and weight are opposite

6 0
2 years ago
Which of the following is NOT a step in the technical design<br> process?
dalvyx [7]

Answer:

incurriculum design process the answer is designs

4 0
2 years ago
For work to be done on an object,
djverab [1.8K]

Answer:B

Explanation:

For work to be done, the object must move some distance as a result of a force

3 0
3 years ago
A car speeds up from 13 m/s to 23 m/s in 30 seconds. What is the
Lapatulllka [165]

acceleration of the car = 0.33 m/s²

Explanation:

To calculate the acceleration of the car we use the following formula:

acceleration = change in velocity / time

change in velocity = final velocity - initial velocity

change in velocity = 23 m/s - 13 m/s = 10 m/s

change in velocity = 10 m/s

acceleration = 10 m/s / 30 s

acceleration = 0.33 m/s²

Learn more about:

acceleration

brainly.com/question/4134594

brainly.com/question/1213762

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8 0
3 years ago
The position of a car at time t is given by the function p(t)=t2 2t−4. What is the velocity when p(t)=11? assume t≥0
AysviL [449]

The velocity when function p(t)=11 is 8 .

According to the question

The position of a car at time t  represented by function :

p(t)=t^{2} +2t-4

Now,

When  function p(t) = 11 , t will be

p(t)=t^{2} +2t-4

11 = t²+2t-4

0 = t² + 2t - 15

or

t² +2t-15 = 0

t² +(5-3)t-15 = 0

t² +5t-3t-15 = 0

t(t+5)-3(t+5) = 0

(t-3)(t+5) = 0  

t = 3 , -5  

as t cannot be -ve as given ( t≥0)

so,

t = 3

Now,

the velocity when p(t)=11

As we know velocity = \frac{position}{time}

therefore to get the value of velocity from  function p(t)

we have to differentiate the function with respect to time

\frac{d(p(t))}{dt} =\frac{d}{dt} (t^{2} +2t-4)

v(t) = 2t + 2  

where v(t) = velocity at that time

as t = 3 for  p(t)=11  

so ,

v(t) = 2t + 2  

v(t) = 2*3 + 2  

v(t) = 8

Hence, the velocity when function p(t)=11 is 8 .

To know  more about function here:

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4 0
2 years ago
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