Answer:
The definition is defined throughout the clarification section beneath, and according to the particular circumstance.
Explanation:
- Although water samples were supplemented with purified water, the amount of EDTA has would be smaller.
- Since there are fewer ions throughout purified water, most of the ions are eliminated throughout distillation, less utilized EDTA.
- Complex calcium formation including EDTA will be less complex. Samples used throughout the starting include several Ca⁺², Mg²⁺ ions that have not been found in pure water, causing fewer EDTA volume to enter the final stages.
Answer:
2.0 M
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 2.93 g
- Volume of the solution: 0.025 L
Step 2: Calculate the moles corresponding to 2.93 g of NaCl
The molar mass of NaCl is 58.44 g/mol.
2.93 g × 1 mol/58.44 g = 0.0501 mol
Step 3: Calculate the molarity of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.0501 mol/0.025 L = 2.0 M
At pH 3.70, H2SO4 can be regarded as being fully dissociated. The dissociation reaction is
H₂SO₄(l) --> 2H⁺(aq) + SO₄²⁻(aq)
Since pH = -log₁₀[H⁺]
[H⁺] = 
= 
[H⁺] = 2 x 10⁻⁴ M
Since there are 2 moles of H⁺ for every mole of H₂SO₄
[H₂SO₄] = 0.5 * [H⁺]
=0.5 * 2 x 10⁻⁴ M
[H₂SO₄] = 1 x 10⁻⁴ M
Convert the amount of rain and the area into SI units
Rain = 1.00 in * 0.0254 m/in
Rain = 0.0254 m
Area = 1600 miles² * 2589988.11 m²/miles² = 4.661 x 10⁹ m²
Calculate the volume of water
Volume = Rain * Area
=0.0254 m * 4.661 x 10⁹
Volume = 1.184 x 10⁸ m³
Calculate the number of kilo moles of H₂SO₄
kilo moles H₂SO₄ = [H₂SO₄] * Volume
=1.0 x 10⁻⁴ M * 1.184 x 10⁸ m³
kilo moles H₂SO₄ = 11,839 k mole
Calculate the mass of H₂SO₄
mass H₂SO₄ = kilo moles H₂SO₄ * MW H₂SO₄
= 11839 k mol * 98.07848 kg/kmol
mass H₂SO₄ = 1.16 x 10⁶ kg H₂SO₄
I believe that the answer would be D, both the speaker and the microphone