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vredina [299]
2 years ago
7

There are TWO isotopes of chlorine. Under normal conditions, chlorine exists as diatomic molecule, Cl₂. The mass of the Cl₂ mole

cule is the sum of masses of the two atoms in the molecule. The mass spectrum of Cl₂ has three peaks, as shown below. From this data, what is the mass of the heavier isotope of chlorine (in amu)?
Peak 1- 69.938 amu
Peak 2- 71.935 amu
Peak 3- 73.932 amu
Chemistry
1 answer:
astraxan [27]2 years ago
4 0

The the mass of the heavier isotope of chlorine (in amu) is 73.932 amu.

<h3>What are isotopes?</h3>

The term isotopes refers atoms that have the same atomic number but different mass number. We must know that all these atoms belong to the same element an differ only in the number of neutrons present in the atom of the element. Hence isotopes are different atoms of the same element hence they have the same chemical properties or reactivity. The mass spectrum is able to show the masses of each of the isotopes according to their order of relative abundance in nature.

Looking at the peaks, we know that the heaviest isotope is the one whose mass will have the highest peak as shown in the mass spectrum of the element as shown. Thus, the the mass of the heavier isotope of chlorine (in amu) is 73.932 amu. The mass spectrum of element also shows this fact.

Learn more about Isotopes:brainly.com/question/11680817

#SPJ1

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3 years ago
What is the empirical formula of a compound that is 24.42 % calcium, 17.07 % nitrogen, and 58.5% oxygen?
REY [17]

Answer:

CaN_{2} O_{6}

Explanation:

When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.

So:

24.42 % = 24.42 g Ca, 17.07% = 17.07g N, 58.5% = 58.5g O

The next step is to divide each mass by their molar mass to convert your grams to moles.

24.42/40.08 = 0.6092 mol

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Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subcripts) of the empircal formula.

0.6092 mol/0.6092 mol = 1

1.218 mol/0.6092 mol = 2

3.680 mol/0.6092 mol = 6

So the empirical formula is CaN_{2} O_{6}

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