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vredina [299]
2 years ago
7

There are TWO isotopes of chlorine. Under normal conditions, chlorine exists as diatomic molecule, Cl₂. The mass of the Cl₂ mole

cule is the sum of masses of the two atoms in the molecule. The mass spectrum of Cl₂ has three peaks, as shown below. From this data, what is the mass of the heavier isotope of chlorine (in amu)?
Peak 1- 69.938 amu
Peak 2- 71.935 amu
Peak 3- 73.932 amu
Chemistry
1 answer:
astraxan [27]2 years ago
4 0

The the mass of the heavier isotope of chlorine (in amu) is 73.932 amu.

<h3>What are isotopes?</h3>

The term isotopes refers atoms that have the same atomic number but different mass number. We must know that all these atoms belong to the same element an differ only in the number of neutrons present in the atom of the element. Hence isotopes are different atoms of the same element hence they have the same chemical properties or reactivity. The mass spectrum is able to show the masses of each of the isotopes according to their order of relative abundance in nature.

Looking at the peaks, we know that the heaviest isotope is the one whose mass will have the highest peak as shown in the mass spectrum of the element as shown. Thus, the the mass of the heavier isotope of chlorine (in amu) is 73.932 amu. The mass spectrum of element also shows this fact.

Learn more about Isotopes:brainly.com/question/11680817

#SPJ1

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An astronomer observes an asteroid in the solar system. He notes that the asteroid is three times farther from the Sun than Eart
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Answer:

3 AU

Explanation:

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7 0
3 years ago
6. Consider the reaction: CzHo (g) + 02 (8) - 4 CO2(g) + 6H2O (1)
deff fn [24]

Answer:

1120 gm

Explanation:

6. Consider the reaction: CzHo (g) + 02 (8) - 4 CO2(g) + 6H2O (1)

(a) Balance the equation.

(b) How many grams of oxygen are required to react with 10 moles of ethane for a complete

combustion reaction?

FIRST, CORRECT THE EQUATION THEN BALANCE

2C2H6(G) + 7O2------------>  4CO2  + 6H2O

so for 10 moles of ethane, we need

7 X 5 = 35 MOLES O2

=35 MOLES O2

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6 0
3 years ago
Use the ideal gas law to calculate the concentrations of nitrogen and oxygen present in air at a pressure of 1.0 atm and a tempe
notka56 [123]

Answer:

[N₂] = 0.032 M

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Ideal Gas Law → P . V = n .  R . T

We assume that the mixture of air occupies a volume of 1 L

78% N₂ → Mole fraction of N₂ = 0.78

21% O₂  → Mole fraction of O₂ = 0.21

1% another gases  → Mole fraction of another gases = 0.01

In a mixture, the total pressure of the system refers to total moles of the mixture

1 atm . 1L = n . 0.082L.atm/mol.K . 298K

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O₂ moles / Total moles = 0.21 → 0.21 . 0.0409 mol = 0.0086 moles O₂

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