Answer : -Angle ACB is the same size as angle GDE
Answer:
c=19.21
<C=90
<B=38.66°
<A=51.34
Step-by-step explanation:
12²+15²=c²
144+225=c²
c=19.21
<C=90
For angle B, the sinB=Opposite over Hypotenuse
sinB=12/19.21
sinB=0.62467
B=sin^-1(0.62467)
<B=38.66°
To find A, 180-90-38.66
<A=51.34
It is a mixed number because mixed mumbers have higher numerator than the denominator
Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
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