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kozerog [31]
4 years ago
6

Which of the following factors does not affect soil formation? a. precipitation b. time c. erosion d. none of the above

Chemistry
2 answers:
Keith_Richards [23]4 years ago
7 0

Answer: Option (a) is the correct answer.

Explanation:

Precipitation is defined as the formation of a solid in a liquid which is not soluble.

Therefore, presence of an insoluble solid substance does not affect soil formation.

Whereas when natural forces like wind, water etc which erode away rocks and soil are known as erosion. Also, time is a factor that also affects the soil formation.

For example, in rainy season due to heavy rain soil erosion occurs which affects the soil formation.

laiz [17]4 years ago
3 0

the answer is a,) because it particpates a substance from a solution. hope this helps

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A glow stick contains a glass vial with chemicals. When the glow stick is bent, the vial breaks
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When you freeze the already cracked glow stick the chemical reactions are slowed down. When you take it out of the freezer and it reaches room temperature the chemical reaction will go on as 'normal'. XD hope this helps

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5 0
3 years ago
Nitric oxide (NO) from car exhaust is a primary air pollutant. Calculate the equilibrium constant for the reaction
viva [34]

This problem is asking for the equilibrium constant at two different temperatures by describing the chemical equilibrium between gaseous nitrogen, oxygen and nitrogen monoxide at 25 °C and 1496 °C as the room temperature and the typical temperature inside the cylinders of a car's engine respectively:

N₂(g) + O₂(g) ⇄ 2 NO(g)

Thus, the calculated equilibrium constants turned out to be 6.19x10⁻³¹ and 9.87x10⁻⁵ at the aforementioned temperatures, respectively, according to the following work:

There is a relationship between the Gibbs free energy, enthalpy and entropy of the reaction, which leads to the equilibrium constant as shown below:

\Delta _rG=\Delta _rH-T\Delta _rS\\\\\Delta _rG=-RT ln(K)

Which means we can calculate the enthalpy and entropy of reaction and subsequently the Gibbs free energy and equilibrium constant. In such a way, we calculate these two as follows, according to the enthalpies of formation and standard entropies of N₂(g), O₂(g) and NO(g) since these are assumed constant along the temperature range:

\Delta _rH=2*90.25 kJ/mol - (0 kJ/mol+0 kJ/mol)=180.5kJ/mol\\\\\Delta _rS=2*(0.211 kJ/mol*K)-(0.192kJ/mol*K+0.205kJ/mol*K)=0.025kJ/mol*K

Then, we calculate the Gibbs free energy of reaction at both 25 °C and 1496 °C:

\Delta _rG_{25\°C}=180.5-(25+298.15)*0.025=172.42kJ/mol\\\\\Delta _rG_{1496\°C}=180.5-(1496+298.15)*0.025=135.65kJ/mol

And finally, the equilibrium constants derived from the general Gibbs equation and Gibbs free energies of reaction:

K=exp(-\frac{\Delta _rG}{RT} )\\\\K_{25\°C}=exp[-\frac{172420 J/mol}{(8.3145\frac{J}{mol*K})(298.15K)} ]=6.19x10^{-31}\\\\K_{1496\°C}=exp[-\frac{135650J/mol}{(8.3145\frac{J}{mol*K})(1769K)} ]=9.87x10^{-5}

Learn more:

  • (Gibbs free energy) brainly.com/question/15213613
4 0
3 years ago
Assume that a raindrop has a volume of 3.48 cm3. If you had an Avogadro’s number of raindrops that just filled a cubic box. What
N76 [4]
Answer is: <span>edge of the length of the box measured is 1280,57 kilometers.
</span>V(raindrop) = 3,48 cm³.
V(cubic box) = 3,48 cm³ · 6,023·10²³.
V(cubic box) = 2,1·10²⁴ cm³.
V(cubic box) = 2,1·10²⁴ cm³ ÷ 10¹⁵.
V(cubic box) = 2,1·10⁹ km³.
r(cubic box) = ∛2,1·10⁹ km³.
r(cubic box) = 1280,57 km.
6 0
3 years ago
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