Answer:
Option (2)
Explanation:
Cohesion is usually defined as the contrasting property by which the water molecules are attached to one another, and adhesion is the property by which the molecular substances are linked to the molecules of other substances.
Since, the water molecules are able to form inter-molecular hydrogen bonding, so they are comprised of strong cohesive force.
And, as the water molecules are able to stick to the walls of the container, so they tend to show more of the properties for adhesion.
Thus, according to the given condition, water molecules are sticking to other substances and this is the property of adhesion.
Hence, the correct answer is option (2).
A lone oxygen atom has 6 electrons in its outer shell which is not very stable, whereas as full octet (8 outer shell electrons) is stable. In order to achieve this two oxygen atoms will share 4 electrons, each contributing 2 electrons. Since these electrons exist within the orbitals of both atoms, to oxygen atoms essentially achieve a full octet.
4 3 and 5 are wrong:)
4 is true and 5 is false
4. insulators are really thick materials that keep electrons within their space.
For example, a charger the rubber is the insulators and the electrons are flowing inside of the charger so you don't get shocked.
5. without the force of attraction, there are no atoms:)
for number 3, its a trick question
Hope this helped!
(learned these this year so I didn't forget them:)
Answer:
a and b are correct
Explanation:
This because both are aqueous solutions,therefore, identity of solvent is same that is water.
And because both solutions are non electrolyte they would not ionize in solution, and for the same concentration, the freezing point of both solution would also be same. Since depression in freezing point is a colligative property this means that it depends on number of solute particles not nature of particles
.
Hence answer is that their freezing points and Identity of the solvent shall remain the same.
We calculate first for the number of moles of gases in the sample through the ideal gas equation.
n = PV/RT
n = (725 mmHg/760 mmHg/atm)(0.255 L) / (0.0821 L.atm/mol.K)(65 + 273.15)
n = 8.76 x 10^-3 mol
Then, we calculate for the mol N2 using the ratio of the pressure.
n N2 = (8.76 x 10^-3 mols)(231 mmHg/725 mmHg)
n N2 = 2.79 x 10^-3 moles
Then, multiply the value with the molar mass of N2 which is 28 grams per mol giving us the answer of 0.078 grams.
