3 years ago

What’s this molecule called?

Chemistry

1 answer:

agasfer [191]3 years ago

8 0

Answer:

Isobutylcyclopentane (C9H18).

Explanation:

A carbon is present at each corner of the cyclo structure (i-e cyclopentane).

Each carbon is bonded with two hydrogen atom except the one containing the side chain defined as isobutane. For the purpose of nomenclature the isobutane is referred as isobutyl.

You might be interested in

Which kingdom contains both unicellular and multicellular eukaryotic organisms?

german

The answer is B). Fungi

I’m sorry if this is wrong but I’m pretty sure it’s not

4 0

3 years ago

Geologists may choose to lick a mineral to identify it. What mineral is the geologist expecting with this test?

Archy [21]

<span>NaCl (halite) or KCl (sylvite) </span>

8 0

3 years ago

A scientist observes how a particular South American bird cares for its young. Why is a field study an appropriate type of scien

mixer [17]

The best answer would be A. Hope i helped

7 0

3 years ago

A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.

Lubov Fominskaja [6]

Answer:

$Ag_2SO_4$

Explanation:

Formula for the calculation of no. of Mol is as follows:

$mol=\frac{mass\ (g)}{molecular\ mass}$

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

$mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol$

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

$mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol$

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

$mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol$

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

$Ag, \frac{0.05305}{0.02657} \approx 2$

$S, \frac{0.02657}{0.02657} \approx 1$

$O, \frac{0.10594}{0.02657} \approx 4$

Therefore, empirical formula of the compound = $Ag_2SO_4$

7 0

4 years ago

Read 2 more answers

Calculate the molarity of a solution that contains 3.00 grams Na2SO4 in 25 mL of solution.

Naddik [55]

Answer:

M Na2SO4 sln = 0.8448 M

Explanation:

molarity (M) [=] mol/L

∴ mass Na2SO4 = 3.00 g

∴ volume soln = 25 mL = 0.025 L

∴ molar mass Na2SO4 = 142.04 g/mol

⇒ mol Na2SO4 = (3.00 g)*(mol/142.04 g) = 0.02112 mol

⇒ M Na2SO4 sln = (0.02112 mol/0.025 L ) = 0.8448 M

3 0

4 years ago