The answer is B). Fungi
I’m sorry if this is wrong but I’m pretty sure it’s not
<span>NaCl (halite) or KCl (sylvite) </span>
Answer:

Explanation:
Formula for the calculation of no. of Mol is as follows:

Molecular mass of Ag = 107.87 g/mol
Amount of Ag = 5.723 g

Molecular mass of S = 32 g/mol
Amount of S = 0.852 g

Molecular mass of O = 16 g/mol
Amount of O = 1.695 g

In order to get integer value, divide mol by smallest no.
Therefore, divide by 0.02657



Therefore, empirical formula of the compound = 
Answer:
M Na2SO4 sln = 0.8448 M
Explanation:
∴ mass Na2SO4 = 3.00 g
∴ volume soln = 25 mL = 0.025 L
∴ molar mass Na2SO4 = 142.04 g/mol
⇒ mol Na2SO4 = (3.00 g)*(mol/142.04 g) = 0.02112 mol
⇒ M Na2SO4 sln = (0.02112 mol/0.025 L ) = 0.8448 M