Answer:
1.25 cm/day
Explanation:
An air thickness , (l) = 0.15 cm
Air Temperature =
Mass Diffusion coefficient (D) =
If the air pressure
We are to determine how fast will the water level drop in a day.
From the property of air at T = 20° C
from saturated water properties.
The mass flow of can be calculated as:
where:
R(constant) = 8.314 kJ/mol.K
Since 1 mole = 18 cm ³ of water
will be:
Again:
Converting the above value to cm/day: we have:
= 1.25 cm/day
∴ the rate at which the water level drop in a day = 1.25 cm/day
Answer:
class TestCode {
public static void main(String args[]) {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
int arr[] = new int[n];
int min = Integer.MAX_VALUE;
for(int i = 0;i<n;i++){
arr[i] = scanner.nextInt();
if(min > arr[i]){
min = arr[i];
}
}
for(int i = 0;i<n;i++){
System.out.print((arr[i]-min) + " ");
}
}
}
Answer:
The risks associated with the handling of liquid hydrogen are fire, explosion, asphyxiation and extremely low temperature exposure.
Answer:
From the question, we have two variables
1. userNum1
2. userNum2
And we are to print "userNum1 is negative" if userNum1 is less than 0.
Then Assign userNum2 with 2 if userNum2 is greater than 10.
Otherwise, print "userNum2 is less or equal 10.".
// Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include<iostream>
using namespace std;
int main ()
{
// Declare variables
int userNum1, userNum2;
// Accept input for these variables
cin>>userNum1, userNum2;
// Condition 1
if(userNum1 < 0)
{
cout<<"userNum1 is negative"<<'\n';
}
// Condition 2
if(userNum2 > 10)
{
userNum2 = 2;
}
// If condition is less than 10
else
{
cout<<"userNum2 is less or equal to 10"<<\n;
}
return 0;
}
// End of Program.