Answer:
14.36((14MPa) approximately
Explanation:
In this question, we are asked to calculate the stress tightened in a bolt to a stress of 69MPa.
Please check attachment for complete solution and step by step explanation
Answer:
0.0406 m/s
Explanation:
Given:
Diameter of the tube, D = 25 mm = 0.025 m
cross-sectional area of the tube = (π/4)D² = (π/4)(0.025)² = 4.9 × 10⁻⁴ m²
Mass flow rate = 0.01 kg/s
Now,
the mass flow rate is given as:
mass flow rate = ρAV
where,
ρ is the density of the water = 1000 kg/m³
A is the area of cross-section of the pipe
V is the average velocity through the pipe
thus,
0.01 = 1000 × 4.9 × 10⁻⁴ × V
or
V = 0.0203 m/s
also,
Reynold's number, Re = 
where,
ν is the kinematic viscosity of the water = 0.833 × 10⁻⁶ m²/s
thus,
Re = 
or
Re = 611.39 < 2000
thus,
the flow is laminar
hence,
the maximum velocity = 2 × average velocity = 2 × 0.0203 m/s
or
maximum velocity = 0.0406 m/s
Explanation:
Outer di ameter
Given loading on the cylinder
Helix an gle of the weld form
(i) Normal stress on the plane at angle
is
(ii) Shear stress along an angle of
is

Answer:
what do u call a toothless bear?
a gummy bear.
Explanation: