If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:
(x,y)=((6+2)/2, (3+1)/2)=(4,2)
Now we need to find the radius....the diameter is:
d^2=(6-2)^2+(3-1)^2
d^2=16+4
d^2=20 since d=2r, r=d/2, and r^2=d^2/4 so
r^2=5
The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:
(h,k)=(4,2) from earlier so:
(x-4)^2+(y-2)^2=5
Answer is <span>A.
{2, 4}
................................................</span>
I think It is be but idk as I am in year 7
-4x - 11 = 2(x - 3x) + 13
-4x - 11 = 2x - 6x + 13
-4x - 11 = -4x + 13
-4x + 4x = 13 + 11
0 = 24...incorrect......no solutions for this problem
Answer:
31 is prime. and it’s prime factorization is just 31....
Step-by-step explanation:
