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Alexxx [7]
2 years ago
11

What is the value of 53i 9?

Mathematics
2 answers:
SIZIF [17.4K]2 years ago
4 0

Answer:

D. 125i

Step-by-step explanation:

just took the test on edge2020

Zielflug [23.3K]2 years ago
3 0

Answer:

125i

Step-by-step explanation:

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Can someone pls help out
weqwewe [10]

Answer:

A. 99.87%

Step-by-step explanation:

i don't explain things good

6 0
3 years ago
Please help me find the slope thank u
Rzqust [24]
Y2-Y1
Over X2-X1 and then there is your slode
6 0
3 years ago
Which two equations are true?(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)=6.6×10−10 (6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.
tiny-mole [99]

let me edit your question as:

Which two equations are true?

<u>Eq1:</u>

(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)

<u>Eq2:</u>

6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)

<u>Eq3:</u>

2.7×103(7.5×106)−(2.5×106)=5×100

Answer:

No one is true

Step-by-step explanation:

let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.

Using PEMDAS rule we are simplifying the equations as;

<u>Eq1:</u>

(2*10-4)+(1.5*10-4)=3.5*10-4(3*10-5)+(2.2*10-5)\\(16)+(11)=35-4(25)+(17)\\27=35-100+17\\27=-48\\

<u>Eq2:</u>

<u></u>6.6*10-10(6.3*10-1)-(2.1*10-1)=3*10-1(5.4*103)-(2.7*103)\\66-10(62)-(20)=30-1(556.2)-278.1\\66-620-20=30-556.2-278.1\\-574=-804.1<u></u>

<u>Eq3:</u>

2.7*103(7.5*106)-(2.5*106)=5*100\\221089.5-265=500\\220824.5=500\\

<u>we observed that none of the equation has two same values on both sides thus none of the three equations is true.</u>

<u>Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true</u>

8 0
3 years ago
Please help me :)))!!!!!!
astraxan [27]

Answer:

16 × <u><em>X </em></u>+ 3=

Step-by-step explanation:

u will get your answer

4 0
3 years ago
A club has 10 members.
TEA [102]
That is the combination of 10 over 3, which is calculated as the quotient of factorials:
n!/k!(n-k)!
where n = 10 and k = 3:
= 10!/3!(10 - 3)!
= 10!/3!*7!
= (10*9*8)/(3*2*1)
= 720/6
= 120
therefore there a re 120 possible different groups
6 0
3 years ago
Read 2 more answers
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