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3 years ago

The equation Y-3--2(x+5) is written in point-slope form. What is the y-intercept of the line?

Mathematics

1 answer:

givi [52]3 years ago

4 0

Answer:

B. -7

Step-by-step explanation:

I'm assuming this equation is y-3=-2(x+5)

Slope intercept form is y = -2 x +-7

In y=mx+b, b is the y-intercept.

b=-7

Hope this helps!

(please mark brainliest)

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ANSWER:

$\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4$

STEP-BY-STEP EXPLANATION:

We have the following equation:

$f(x)=\sqrt{x}-4$

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

$\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\ \\ \sqrt{f^{-1}(x)}=x+4 \\ \\ f^{-1}(x)=(x+4)^2 \end{gathered}$

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1 year ago

What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of .

hjlf

The correct question is
What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3

we have that
point (1,-2)
slope m=1/3
so
y-y1=m*(x-x1)-----> y+2=(1/3)*(x-1)----> multiply by 3---> 3y+6=x-1
x-3y-1-6=0------> x-3y-7=0

the answer is
x - 3y - 7 = 0

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