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Tju [1.3M]
3 years ago
15

When CO2 decomposes into oxygen and carbon, it gives a gram ratio of 2.67:1 O2:C. When a 32.4g of CO2 decomposes, how many grams

of carbon are produced, and how many grams of of O2 are produced? Hint(What is the total of carbon and oxygen produced)
Chemistry
1 answer:
Rufina [12.5K]3 years ago
6 0

Answer : The mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

CO_2\rightarrow O_2+C

As we are given:

\text{Mass of }O_2}:\text{Mass of }C=2.67:1{

According to the law of conservation of mass,

Total mass of CO_2 = Mass of O_2 + Mass of C

Total mass of CO_2 = 2.67 + 1 = 3.67 g

Now we have to calculate the mass of O_2 and C.

\text{Mass of }O_2=\frac{\text{Given mass of }CO_2}{\text{Total mass of }CO_2}\times \text{Given mass of }O_2=\frac{32.4g}{3.67g}\times 2.67=23.6g

and,

\text{Mass of }C=\frac{\text{Given mass of }CO_2}{\text{Total mass of }CO_2}\times \text{Given mass of }C=\frac{32.4g}{3.67g}\times 1=8.83g

Therefore, the mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.

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its 0.163 g

Explanation:

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PO 2 =P t −P H 2 O

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=  737.6 mmHg

From the ideal gas equation we write.

W= RT/PVM = (0.0821Latm/Kmol)(273+24)K(0.974atm)(0.128L)(32.0g/mol/) =0.163g

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2 years ago
True or False? The following set of quantum numbers is acceptable (0, 0, 0, +1/2). Explain.
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Answer:

False

Explanation:

The values of the principal quantum number range from 1- infinity. This implies that there is no such thing as an energy level with n=0.

Hence this can not be an acceptable set of quantum numbers when n=0.

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What are the necessary ingredients for photosynthesis
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An atom of 70kr has a mass of 69. 955264 amu. mass of1h atom = 1. 007825 amu mass of a neutron = 1. 008665 amu. calculate the bi
Leno4ka [110]

The binding energy in MeV per atom is - 63284.56 Mev.

The amount of energy needed to detach a particle from a system of particles or to disperse every particle in the system is known as the binding energy. Subatomic particles in atomic nuclei, electrons attached to atom's nuclei, and atoms and ions bonded together in crystals are three examples of where binding energy is very relevant.

If we have a nucleus with Z protons and N neutrons and mass MA, where A = Z + N then its binding energy in MeV is given by: Eb(MeV) = (Zmp + Nmn - MA) x 931.494 MeV/u

Mass of atom = 69.955264 amu

Mass of proton = 1.007825 amu

Mass of neutron = 1.008665 amu

Binding energy, Mev = (Zmp + Nmn - M) × 931.494MeV/u

                                    = ( 1.007825 + 1.008665 -  69.955264) × 931.494

                                    = - 67.938774 × 931.494

                                    = - 63284.56 Mev

Therefore, the binding energy in MeV per atom is - 63284.56 Mev.

Learn more about binding energy here:

brainly.com/question/16795451

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