Ask question

Ask question

All categories

3 years ago

14

List the types of properties in science

1 answer:

nata0808 [166]3 years ago

8 0

Cells, antibodies…

jk don’t actually try this, be more specific about the question?

You might be interested in

Phosphorus has an atomic mass of 31 and an atomic number of 15, so the number of neutrons must be _______________.

Nikitich [7]

Remember this:

atomic mass= atomic number + number of neutrons

The atomic number (same thing as number of protons) in this case is 15. The atomic mass is 31.

So, we subtract 15 from 31 to find the number of neutrons.

31-15=16

16 neutrons!!!

6 0

3 years ago

A helium filled ballon at sea level gas a volume of 2.1L at 0.998 atm and 36C if it is released and rises to an elevation where

expeople1 [14]

Answer:

2.268 L

Explanation:

According to Ideal Gas Law, " The Volume of a given mass of gas is inversely proportional to the applied Pressure and directly proportional to applied temperature, ". Mathematically the initial and final states of gas are given as,

P₁ V₁ / T₁ = P₂ V₂ / T₂ ----------- (1)

Data Given;

P₁ = 0.998 atm

V₁ = 2.1 L

T₁ = 36 °C = 309 K

P₂ = 0.90 atm

T₂ = 28 °C = 301 K

V₂ = ??

Solving equation 1 for P₂,

V₂ = P₁ V₁ T₂ / T₁ P₂

Putting values,

V₂ = (0.998 atm × 2.1 L × 301 K) ÷ (309 K × 0.90 atm)

V₂ = 2.268 L

7 0

3 years ago

The products of a chemical reaction are chemically different substances than the reactants of a chemical reaction.

svlad2 [7]

this statement is true

Answer:

<em>Hope </em><em>it </em><em>helps </em><em>u</em>

7 0

3 years ago

Consider the reaction 2N2(g) O2(g)2N2O(g) Using the standard thermodynamic data in the tables linked above, calculate Grxn for t

ratelena [41]

Answer:

$\Delta G^0 _{rxn} = 207.6\ kJ/mol$

ΔG ≅ 199.91 kJ

Explanation:

Consider the reaction:

$2N_{2(g)} + O_{2(g)} \to 2N_2O_{(g)}$

temperature = 298.15K

pressure = 22.20 mmHg

From, The standard Thermodynamic Tables; the following data were obtained

$\Delta G_f^0 \ \ \ N_2O_{(g)} = 103 .8 \ kJ/mol$

$\Delta G_f^0 \ \ \ N_2{(g)} =0 \ kJ/mol$

$\Delta G_f^0 \ \ \ O_2{(g)} =0 \ kJ/mol$

$\Delta G^0 _{rxn} = 2 \times \Delta G_f^0 \ N_2O_{(g)} - ( 2 \times \Delta G_f^0 \ N_2{(g)} + \Delta G_f^0 \ O_{2(g)})$

$\Delta G^0 _{rxn} = 2 \times 103.8 \ kJ/mol - ( 2 \times 0 + 0)$

$\Delta G^0 _{rxn} = 207.6\ kJ/mol$

The equilibrium constant determined from the partial pressure denoted as $K_p$ can be expressed as :

$K_p = \dfrac{(22.20)^2}{(22.20)^2 \times (22.20)}$

$K_p = \dfrac{1}{ (22.20)}$

$K_p$ = 0.045

$\Delta G = \Delta G^0 _{rxn} + RT \ lnK$

where;

R = gas constant = 8.314 × 10⁻³ kJ

$\Delta G =207.6 + 8.314 \times 10 ^{-3} \times 298.15 \ ln(0.045)$

$\Delta G =207.6 + 2.4788191 \times \ ln(0.045)$

$\Delta G =207.6+ (-7.687048037)$

$\Delta G =$ 199.912952 kJ

ΔG ≅ 199.91 kJ

7 0

4 years ago

How many c atoms are in 2 mol of sucrose?

castortr0y [4]

12 carbon atoms<span>, 22 hydrogen atom, and 11 oxygen atoms in 2 moles of sucrose</span>

7 0

4 years ago