The natural abundance of bromine in general in nature is 100%.
This means that:
the natural abundance of Br-79 + the natural abundance of Br-80 = 100
We know that the natural abundance of Br-79 is 50.69%. This means that the natural abundance of Br-80 is the rest of the 100%.
Natural abundance of Br-80 = 100% - 50.69% = 49.31%
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Answer:
I am pretty sure that it is C
Explanation:
Answer:
Average atomic mass of carbon = 12.01 amu.
Explanation:
Given data:
Abundance of C¹² = 98.89%
Abundance of C¹³ = 1.11%
Atomic mass of C¹² = 12.000 amu
Atomic mass of C¹³ = 13.003 amu
Average atomic mass = ?
Solution:
Average atomic mass of carbon = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass of carbon = (12.000×98.89)+(13.003×1.11) /100
Average atomic mass of carbon= 1186.68 + 14.43333 / 100
Average atomic mass of carbon = 1201.11333 / 100
Average atomic mass of carbon = 12.01 amu.
