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3 years ago

13

Which expression do you solve first

2 answers:

hammer [34]3 years ago

8 0

Answer:

The first thing you would solve is 10^2.

Step-by-step explanation:

This is because in the order of operations, parenthesis comes first - which you don't have any of - and then exponents come second.

Minchanka [31]3 years ago

4 0

10^2 is the expression that you should solve first

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Shtirlitz [24]

Answer:

3) Not equivalent

4) Equivalent

5) Equivalent

(Multiply by two for the last two questions)

4 0

3 years ago

How do you solve :<br><br><img src="https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="Tex

Neporo4naja [7]

$x^2=\dfrac{2}{3}\to x=\pm\sqrt{\dfrac{2}{3}}\\\\x=-\dfrac{\sqrt{2}}{\sqrt3}\ \vee\ x=\dfrac{\sqrt2}{\sqrt3}\\\\x=-\dfrac{\sqrt2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}\ \vee\ x=\dfrac{\sqrt2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}\\\\\boxed{x=-\dfrac{\sqrt6}{3}\ \vee\ x=\dfrac{\sqrt6}{3}}$

5 0

3 years ago

The number 75 can be written as the sum of the squares of 3 different positive integers. what is the sum of these 3 integers?

muminat

The square numbers smaller than 75 are 1, 4, 9, 16, 25, 36, 49, 64
1+49+25=75 seems to be the only set possible.
1+7+5=13
the answer is 13

8 0

3 years ago

What is the inverse of the function f(x)=3^x

Leokris [45]

Answer:

$f^{-1}(x) = \log_3(x)$

Step-by-step explanation:

The inverse operation for an exponential ( $a^x$ ) is the logarithm: $\log_a(x)$ .

8 0

3 years ago

In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad

zysi [14]

Answer: a) 0.0792 b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)$ (1)

Similarly ,

$P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792$

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

$P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264$

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0

3 years ago