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3 years ago

Which expression do you solve first

Mathematics

2 answers:

hammer [34]3 years ago

8 0

Answer:

The first thing you would solve is 10^2.

Step-by-step explanation:

This is because in the order of operations, parenthesis comes first - which you don't have any of - and then exponents come second.

Minchanka [31]3 years ago

4 0

10^2 is the expression that you should solve first

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3 years ago

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The bank statement of Ali Co. indicated a current balance of $32,900.10. The current checkbook balance

Grace [21]

Answer:

The reconciled balance =32900.10 which tallies with bank balance.

Step-by-step explanation:

Given that the bank statement of Ali Co. indicated a current balance of $32,900.10

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4 0

3 years ago

How to factor 6n2 - 6n - 12

alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

$6n^2-6n-12 = 6(n^2-n-2)$

We can set this equal to 0 and factor by using the quadratic formula which is:

$x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

So, let's do just that:

$6(n^2-n-2) = 0$

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

$\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}$

$\frac{-1 \pm \sqrt{9} }{2} = {1, -2}$

So, we can write this as:

$6n^2 - 6n - 12 = 6(n-1)(n+2)$

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

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3 years ago

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morpeh [17]

Answer:

The answer should be $\leq$ .

Step-by-step explanation:

Because Right now 13.2 could be bigger than x or it could be equal to x so that's why its $\leq$ .

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