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vovikov84 [41]
3 years ago
10

Identify the mole ratio of water to sodium metal? Determine the number of moles of Sodium that reacted and determine the number

of kg of Sodium that reacted. Sodium is 22.99 g/mol
Chemistry
1 answer:
frozen [14]3 years ago
7 0

Number of moles of sodium reacted is 2 moles. 0.04598 Kg is the mass of sodium that reacted.

Mole fraction is 1 mole ratio is 1:1

Explanation:

Balanced chemical reaction:

2 Na + 2H20 ⇒ 2NaOH + H2 (gas)

atomic mass of sodium = 22.99 g/mol

from the reaction it can be seen that 2 moles of sodium reacted to form 2 moles of sodium hydroxide soluition.

The mass of sodium reacted can be calculated from the formula:

mass = atomic mass of one mole x number of moles

mass = 22.99 x 2

         = 45.98 grams is the mass of sodium, to convert it into kilograms it is divided by 1000

= 0.04598 Kg is the mass of sodium that reacted.

Mole fraction formula is:

\frac{moles of solute}{moles of solution} = mole fraction   ( solute Na = 2 moles, solution is NaOH =2 moles)

putting the values:

\frac{2}{2}

= 1 mole ratio is 1:1

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Give the direction of the reaction, if K >> 1. Give the direction of the reaction, if K >> 1. The forward reaction i
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Answer:

A. for K>>1 you can say that the reaction is nearly irreversible so the forward direction is favored. (Products formation)

B. When the temperature rises the equilibrium is going to change but to know how is going to change you have to take into account the kind of reaction. For endothermic reactions (the reverse reaction is favored) and for exothermic reactions (the forward reaction is favored)

Explanation:

A. The equilibrium constant K is defined as

K=\frac{Products}{reagents}

In any case  

aA +Bb  equilibrium Cd +dD

where K is:

K= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}

[] is molar concentration.

If K>>> 1 it means that the molar concentration of products is a lot bigger that the molar concentration of reagents, so the forward reaction is favored.

B. The relation between K and temperature is given by the Van't Hoff equation

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Where: H is reaction enthalpy, R is the gas constant and T temperature.  

Clearing the equation for K_{2} we get:

K_{2}=\frac{K_{1}}{e^{\frac{-deltaH^{o}}{R}*(\frac{1}{T_{1}} -\frac{1}{T_{2}})}}

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When we have an endothermic reaction we will have a positive exponent so K_{2} will be less than K_{1} the forward reactions is not favored.  

{e^{\frac{-deltaH^{o}}{R}*(\frac{1}{T_{1}} -\frac{1}{T_{2}})}}

5 0
3 years ago
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