Identify the mole ratio of water to sodium metal? Determine the number of moles of Sodium that reacted and determine the number
1 answer:
Number of moles of sodium reacted is 2 moles. 0.04598 Kg is the mass of sodium that reacted.
Mole fraction is 1 mole ratio is 1:1
Explanation:
Balanced chemical reaction:
2 Na + 2H20 ⇒ 2NaOH + H2 (gas)
atomic mass of sodium = 22.99 g/mol
from the reaction it can be seen that 2 moles of sodium reacted to form 2 moles of sodium hydroxide soluition.
The mass of sodium reacted can be calculated from the formula:
mass = atomic mass of one mole x number of moles
mass = 22.99 x 2
= 45.98 grams is the mass of sodium, to convert it into kilograms it is divided by 1000
= 0.04598 Kg is the mass of sodium that reacted.
Mole fraction formula is:
= mole fraction ( solute Na = 2 moles, solution is NaOH =2 moles)
putting the values:
= 1 mole ratio is 1:1
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Answer:
Number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.
Number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.
Total number of ions = 1.49 × 10²³ + 1.49 × 10²³ = 2.98 × 10²³.
Explanation:
1 mole of any compound contains 6.023 × 10²³ molecules.
molecular weight of NaCl is 23 + 35.5 = 58.5 g.
so, 58.5 grams of NaCl makes 1 mole
⇒ 14.5 g of NaCl = = 0.248 moles.
⇒ 0.248 mole contains 0.248 × 6.023×10²³ molecules
= 1.49 × 10²³ molecules.
And 1 molecule contains 1 Na ion and 1 Cl ion.
⇒ number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.
⇒ number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.
Total number of ions = 1.49 × 10²³ + 1.49 × 10²³ = 2.98 × 10²³.