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BabaBlast [244]
3 years ago
12

If irons temperature goes from 50c to 75c in a 20g sample, how many joules of heat were used?

Chemistry
1 answer:
Marina CMI [18]3 years ago
3 0

Answer:

Option D. 230 J

Explanation:

We'll begin by calculating the temperature change of the iron. This can be obtained as follow:

Initial temperature (T₁) = 50 °C

Final temperature (T₂) = 75 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 75 – 50

ΔT = 25 °C

Thus, the temperature change of the iron is 25 °C.

Finally, we shall determine the amount of heat energy used. This can be obtained as follow:

Mass (M) = 20 g

Change in temperature (ΔT) = 25 °C

Specific heat capacity (C) = 0.46 J/gºC

Heat (Q) =?

Q = MCΔT

Q = 20 × 0.46 × 25

Q = 230 J

Thus, the amount of heat used was 230 J

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Explanation:

The first high part is Q4, then the low part is Q7, the following high part is Q6, and the energy moving from the next two high points is Q5 because of the diagram.

5 0
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What do geologists call the underground molten mixture of rock-forming substances, gases, and water that is found in the mantle?
Likurg_2 [28]

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Explanation:

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6 0
3 years ago
Which contains particles having the highest average kinetic energy?
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4 0
3 years ago
Calcium carbonate can be decomposed by heating: CaCO3 - CaO + CO2
Galina-37 [17]

Answer: 13.888g

Explanation:

CaCO3 —> CaO + CO2

From the equation above, 1mole of CaCO3 produces 1mole of CaO. Since the answer is to be expressed in grams, let us covert this mole to grams. This is illustrated below:

MM of CaCO3 = 40 +12 + (16x3) = 40 + 12 + 48 = 100g/mol

MM of CaO = 40 + 16 = 56g/mol

From the equation,

100g of CaCO3 produced 56g CaO

Therefore, 24.8g of CaCO3 will produce Xg of CaO i.e

Xg of CaO = (24.8 x 56) / 100 = 13.888g

Therefore, the theoretical yield of CaO is 13.888g

3 0
3 years ago
the reaction of 50 mL of gas with 50 mL of gas via the equation: Cl2(g) + C2H4(g) ➔ C2H4Cl2 (g) will produce a total of ________
spin [16.1K]

Explanation:

The given data is as follows.

      50 ml of Cl_{2},       50 ml of C_{2}H_{4}

And, it is known that at STP 1 mole of a gas occupies 22.4 L. Hence, moles present in 50 ml of gas are as follows.

          \frac{50}{22.4 \times 1000}      (As 1 L = 1000 ml)

          = 2.23 \times 10^{-3} moles

So, according to the given equation 2.23 \times 10^{-3} moles of Cl_{2} reacts with 2.23 \times 10^{-3} moles of C_{2}H_{4}.

Hence, moles of C_{2}H_{4}Cl_{2} is equal to the moles of C_{2}H_{4} and Cl_{2}.

Therefore, moles of C_{2}H_{4}Cl_{2} = 2.23 \times 10^{-3} moles

           1 mole of C_{2}H_{4}Cl_{2} = 22.4 L

   2.23 \times 10^{-3} moles = 22.4 \times 2.23 \times 10^{-3} moles        

                                = 50 ml of product

Thus, we can conclude that 50 ml of products if pressure and temperature are kept constant.

5 0
4 years ago
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