Answer:
156 g of AlCl₃ will be produced from 3.5 moles of HCl.
Explanation:
Given data:
Number of moles of HCl = 3.5 mol
Grams of AlCl₃ produced = ?
Solution:
Balanced Chemical equation:
3HCl + Al(OH)₃ → AlCl₃ + 3H₂O
Now we will compare the moles of AlCl₃ with HCl from balanced chemical equation.
HCl : AlCl₃
3 : 1
3.5 : 1/3×3.5 = 1.17 mol
Mass of AlCl₃ produced:
Mass = number of moles ×molar mass
Mass = 1.17 mol × 133.341 g/mol
Mass = 156 g
Thus 156 g of AlCl₃ will be produced from 3.5 moles of HCl.
Answer:
The valence electrons in the metal atom in the lattice structure can delocalize and move freely. The electrons are "loosely" connected with their parent atom in the metallic bond because most metals have excess electrons in their outer orbitals above the stable configuration.
Explanation:
Says google
The carbon cycle. (Most likely, I'm unsure)
<u>Answer:</u> The number of moles of ammonium nitrate is 0.004 moles.
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
We are given:
Molarity of 
solution = 0.125 M
Volume of solution = 32.5 mL
Putting values in above equation, we get:
Hence, the number of moles of ammonium nitrate is 0.004 moles.
Particles are measured in atomic mass units, or AMU.
