Answer:6.022 x 10^23 molecules
Explanation: Since one mole of any chemical compound always contains 6.022 x 10^23 molecules, you can calculate the number of molecules of any substance if you know its mass and its chemical formula.
Answer:
Alkylenes: any of the series of unsaturated hydrocarbons containing a triple bond, including acetylene.
alkanes: Alkanes are organic compounds that consist entirely of single-bonded carbon and hydrogen atoms and lack any other functional groups. Alkanes have the general formula CnH2n+2 and can be subdivided into the following three groups: the linear straight-chain alkanes, branched alkanes, and cycloalkanes.
Explanation:
Answer:
The correct answer to the following question will be "90.6 kJ/mol".
Explanation:
The total reactant solution will be:
![(31.8 \ mL+68.9 \ mL)\times 1.07\ g/mL = 107.74 \ g](https://tex.z-dn.net/?f=%2831.8%20%5C%20mL%2B68.9%20%5C%20mL%29%5Ctimes%201.07%5C%20g%2FmL%20%3D%20107.74%20%5C%20g)
The produced energy will be:
![=4.18 \ J/(gK)\times 107.74 \ g\times (28.2-25.0)K](https://tex.z-dn.net/?f=%3D4.18%20%5C%20J%2F%28gK%29%5Ctimes%20107.74%20%5C%20g%5Ctimes%20%2828.2-25.0%29K)
![=450.35\times 3.2](https://tex.z-dn.net/?f=%3D450.35%5Ctimes%203.2)
![=1441.12 \ J](https://tex.z-dn.net/?f=%3D1441.12%20%5C%20J)
The reaction will be:
⇒ ![HCl+NaOH \rightarrow NaCl+H_{2}O](https://tex.z-dn.net/?f=HCl%2BNaOH%20%5Crightarrow%20NaCl%2BH_%7B2%7DO)
Going to look at just the amounts of reactions with the same concentrations, we notice that they're really comparable.
Therefore, the moles generated by NaCl will indeed be:
= ![(\frac{31.8}{1000} \ L)\times (0.500 \ M \ HCl/L)\times \frac{1 \ mol \ NaCl}{1 \ mol \ HCl}](https://tex.z-dn.net/?f=%28%5Cfrac%7B31.8%7D%7B1000%7D%20%5C%20L%29%5Ctimes%20%280.500%20%5C%20M%20%5C%20HCl%2FL%29%5Ctimes%20%5Cfrac%7B1%20%5C%20mol%20%5C%20NaCl%7D%7B1%20%5C%20mol%20%5C%20HCl%7D)
= ![0.0318\times 0.500](https://tex.z-dn.net/?f=0.0318%5Ctimes%200.500)
= ![0.0159 \ mole \ of \ NaCl](https://tex.z-dn.net/?f=0.0159%20%5C%20mole%20%20%5C%20of%20%5C%20NaCl)
Now,
= ![\frac{1441.12 \ J}{0.0159 \ moles \ NaCl}](https://tex.z-dn.net/?f=%5Cfrac%7B1441.12%20%5C%20J%7D%7B0.0159%20%5C%20moles%20%5C%20NaCl%7D)
= ![906364.7](https://tex.z-dn.net/?f=906364.7)
= ![90.6 \ KJ/mol \ NaCl](https://tex.z-dn.net/?f=90.6%20%5C%20KJ%2Fmol%20%5C%20NaCl)
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