Question

A gas that exerts a pressure of ____ psi in a container with a volume of 12.45 L will exert a pressure of 1112 psi when transferred to a container with a volume of 6.531 L. (Solve the ____)

Answer 1

Answer:

A gas that exerts a pressure of 583.33 psi. psi in a container with a volume of 12.45 L will exert a pressure of 1112 psi when transferred to a container with a volume of 6.531 L.

Explanation:

Initial pressure exerted by the gas = $P_1$

Initial volume occupied by the gas = $V_1=12.45 L$

Final pressure exerted by the gas = $P_2=1112 psi$

Final volume of the gas occupied by the gas = $V_2=6.531 L$

Applying Boyle's law:

$P_1\times V_1=P_2\times V_2$

$P_1=\frac{P_2\times V_2}{V_1}=\frac{1112 psi\times 6.531 L}{12.45 L}=583.33 psi$

The initial pressure exerted by the gas was 583.33 psi.

A gas that exerts a pressure of 583.33 psi. psi in a container with a volume of 12.45 L will exert a pressure of 1112 psi when transferred to a container with a volume of 6.531 L.

Answer 2

Here, we may apply Boyle's law, which is mathematically expressed as:
PV = constant
So, we equate the product of the the initial pressure and volume to the product of the final pressure and volume as such:
P * 12.45 = 1112 * 6.53
P = (1112 * 6.53) / 12.45
P = 583.2 PSI