Answer:
Weight = 490 N
Explanation:
The two forces labeled and are the force of gravity and the normal force that the surface acts upon the object. These are equal and in opposite directions cancelling each other.
The other two forces and are both pointing to the right, and therefore add up to give a net force of:
50 N + 75 N = 125 N pointing to the right.
Since the net acceleration of the object is given as 2.5 , we can use it in Newton's equation for the net force on an object to solve for the object's mass:
Notice that since all units are in the SI system, the mass comes directly in kilograms (unit of mass in the SI system)
Now, to find the weight of the object, we multiply its mass times the acceleration of gravity (9.8 ):
Weight =
Again, since all quantities are expressed in SI units, the weight (a force) will come out in units of "Newtons" (N)
Answer is: 354 days.
V = V₀ + g·t.
V - final velocity, V = 3·10⁸ m/s.
V₀ - initial velocity, V₀ = o, because spaceship is in rest.
t - t<span>ime, how long it takes for spaceship to move from one position to another.
</span>g - gravity, g = 9,8 m/s².
t = V÷g = 3,06·10⁷s = 510204min = 88503,4hr = 354 days.
Answer:
σ = 4.1 MPa
Explanation:
Given that
m= 2.5 kg
v= 32 km.hr
v= 8.88 m/s
The kinetic energy of the mass ,KE
KE = mv²/2
KE = 2.5 x 8.88²/2
KE= 98.56 J -------1
The strain energy of the string
----2
KE= E
σ = 4.1 MPa
Answer:
v = 1.85*10^5 m/s
Explanation:
In order to calculate the speed of the electron after it has traveled 1.8m, you first take into account that the electric field generates a desceleration on the electron, because the direction of the electron and electric field are the same.
You use the Newton second law, to calculate the deceleration of the electron:
(1)
q: charge of the electron = 1.6*10^-19C
m: mass of the electron = 9.1*10^-31kg
E: magnitude of the electric field = 9.11*10^-3N/C
a: deceleration = ?
You solve the equation (1) for a, and replace the values of the other parameters:
Next, you use the following formula to calculate the final speed of the electron:
(2)
v: final speed of the electron = ?
vo: initial speed of the electron = 2.0*10^5 m/s
x: distance traveled by the electron = 1.8m
You solve the equation (2) for v and replace the values of the other parameters:
The speed of the electron after it has traveled 1.8m is 1.85*10^5 m/s
To produce a maximum emf of 1.0 V, the angular speed should rotate at 35.368 rad/s.
<h3>What is a uniform magnetic field?</h3>
A uniform magnetic field is depicted by parallel straight lines that are distributed uniformly. The flux path is the same as the path of a tiny magnet's north-seeking pole. The flux channels are continuous, producing closed loops.
For a single loop of wire with a radius of 7.5 cm that rotates about a diameter in a uniform magnetic field of 1.6T. We need to determine the angular speed of rotation for it to produce a maximum electromotive force (emf) of 1.0 V.
Given that:
The radius = 7.5 cm, to convert it to meters, we will divide it by 100.
= (7.5/100) m
= 0.075 m
The area A of the wire is computed by using the formula:
A = πr²
A = π(0.075)²
A = 0.01767 m²
Imagine a coil with N turns with area A rotating at a constant angular velocity (q) inside a flux density of a (B) of a magnetic field, with its axis parallel to the field.
The maximum e.m.f can be computed by using the formula:
Where;
- Magnetic field (B) = 1.6 T
Making the angular speed (ω) the subject of the formula, we have:
ω = 35.368 rad/s
Learn more about the angular speed of a uniform magnetic field here:
brainly.com/question/15856270
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