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3 years ago

Describe a characteristic of each layer of the atmosphere

1 answer:

7 0

Troposphere. The troposphere is the lowest layer of our atmosphere.

Stratosphere. The infamous ozone layer is found within the stratosphere.

Mesosphere. Most meteors burn up in the mesosphere.

Thermosphere. Many satellites actually orbit Earth within the thermosphere

Exosphere. Considered to be the actual "final frontier"

Ionosphere. The electrically charged atoms and molecules that are formed in this way are called ions, giving the ionosphere its name

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What is the frequency if 140 waves pass in 2 minutes?

Paha777 [63]

Answer:

1.16 Hz

Explanation:

frequency, basically, is the number of wave on 1 second

so, in math we write like this

f = n/t

n = number of waves

t = time to do that (in sec)

f = 140/120 = 7/6 Hz

f = 1.16 Hz

8 0

3 years ago

Please help.

LenKa [72]

Mu wildest guess is c 1500

7 0

4 years ago

Read 2 more answers

What part of earth systems interact to form a storm like this hurricane near Florida

Akimi4 [234]

Hurricanes form from interactions between the atmosphere and the oceans. Hope it helps.

7 0

3 years ago

Electrons in a particle beam each have a kinetic energy of 4.0 × 10−17 J. What is the magnitude of the electric field that will

denpristay [2]

Explanation:

Relation between work and change in kinetic energy is as follows.

$W_{net} = \Delta K$

Also, $\Delta K = K_{initial} - K_{final}$

= $(0 - 4.0 \times 10^{-17})$ J

= $-4.0 \times 10^{-17}$ J

Let us assume that electric force on the electron has a magnitude F. The electron moves at a distance of 0.3 m opposite to the direction of the force so that work done is as follows.

w = -Fd

$-4.0 \times 10^{-17} J = -F \times 0.3 m$

F = $1.33 \times 10^{-16}$

Therefore, relation between electric field and force is as follows.

E = $\frac{F}{q}$

= $\frac{1.33 \times 10^{-16}}{1.60 \times 10^{-19} C}$

= $0.831 \times 10^{3}$ C

Thus, we can conclude that magnitude of the electric field that will stop these electrons in a distance of 0.3 m is $0.831 \times 10^{3}$ C.

3 0

3 years ago

An electron has a velocity of 1.50 km/s (in the positive x direction) and an acceleration of 2.00 ✕ 1012 m/s2 (in the positive z

olga nikolaevna [1]

Answer:

see explanation

Explanation:

Given that,

velocity of 1.50 km/s = 1.50 × 10³m/s

acceleration of 2.00 ✕ 1012 m/s2

electric field has a magnitude of strength of 18.0 N/C

$\bar F= q[\bar E + \bar V \times \bar B]\\\\\bar F = [\bar E + \bar V \times ( B_x \hat i +B_y \hat j +B_z \hat z )]\\\\\\m \bar a = [\bar E + \bar V \times ( B_x \hat i +B_y \hat j +B_z \hat z )]$

$9.1 \times 10^-^3^1 \times 2\times 10^1^2 \hat k=-1.6\times10^-^1^9 \hat k [18\hat k+ 1.5\times 10^3 \hat i \times (B_x \hat i +B_y \hat j +B_z \hat k)]$ $42.2 \times 10^-^1^9 \hat k = -2.4 \times 10^1^6B_y \hat k + 2.4 \times 10 ^1^6 \hat j B_z\\$

$B_x = undetermined$

$B_y = \frac{42.2 \times 10^-^1^9}{-2.4 \times 10^-^1^6} \\\\= - 0.0176 T$

$B_z = 0T$

8 0

4 years ago