Porque fueron tan importantes las aportaciones de Galileo Galilei en la construcción y validación del conocimiento científico

To accelerate, an object must *

Sonja [21]

Answer: Not 100% sure but I think it’s C.

Hope this helps! ^^

4 0

3 years ago

How much momentum does a 10 kg object have when is moving 30 m/s

nikklg [1K]

P = m x v

P = 30 x 10
=300

3 0

3 years ago

Two light bulbs have resistances of 400 Ω and 800 ΩThe two light bulbs are connected in series across a 120- V line. Find the cu

Natasha2012 [34]

1) Current in each bulb: 0.1 A

The two light bulbs are connected in series, this means that their equivalent resistance is just the sum of the two resistances:

$R_{eq}=R_1 + R_2 = 400 \Omega + 800 \Omega=1200 \Omega$

And so, the current through the circuit is (using Ohm's law):

$I=\frac{V}{R_{eq}}=\frac{120 V}{1200 \Omega}=0.1 A$

And since the two bulbs are connected in series, the current through each bulb is the same.

2) 4 W and 8 W

The power dissipated by each bulb is given by the formula:

$P=I^2 R$

where I is the current and R is the resistance.

For the first bulb:

$P_1 = (0.1 A)^2 (400 \Omega)=4 W$

For the second bulb:

$P_1 = (0.1 A)^2 (800 \Omega)=8 W$

3) 12 W

The total power dissipated in both bulbs is simply the sum of the power dissipated by each bulb, so:

$P_{tot} = P_1 + P_2 = 4 W + 8 W=12 W$

3 0

3 years ago

Think of an animal and list two resources that it might compete for in its community . Then describe what adaptions the animals

Viefleur [7K]

An animal is a lion, it may compete for food and it’s territory. The animal may have to fight other animals to get these things

6 0

3 years ago

"A circuit consists of a battery and two resistors connected in parallel. If the resistance in both resistors is doubled, and th

sveticcg [70]

Let's call R the value of the resistance of the two resistors. In the first situation, the resistors are connected in parallel, so their equivalent resistance is given by:
$\frac{1}{R_{eq}}=\frac{1}{R}+\frac{1}{R}=\frac{2}{R}$
which means:
$R_{eq}=\frac{R}{2}$
And calling I the current in the circuit, the voltage is given by Ohm's law:
$V=IR_{eq}=\frac{IR}{2}$

In the second situation, the resistance of each resistor is doubled: R'=2R. So, the equivalent resistance in this case is given by
$\frac{1}{R_{eq}}=\frac{1}{2R}+\frac{1}{2R}=\frac{2}{2R}=\frac{1}{R}$
which means
$R_{eq}=R$
And the new voltage is given by:
$V'=IR_{eq}=IR=2V$
which is twice the original voltage, so the voltage has doubled.

7 0

3 years ago

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