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pav-90 [236]
3 years ago
13

(WILL MARK BRAINLIEST) PLZ HELP ASAP

Chemistry
2 answers:
ArbitrLikvidat [17]3 years ago
3 0

Answer:

a) 2NaOH(aq) + CuSO4(aq) -------------> Cu(OH)2(s) + Na2SO4(aq)

b) Ca(OH)2(aq) + CO2(g) --------------> CaCO3 + H2O (this is already balanced)

c) Pb(NO3)2 + H2SO4 --------> PbSO4 + 2HNO3.

d) 2KNO3 ------> 2KNO2 + O2

e) H2SO4 + 2(NaOH) -----> Na2SO4 + 2(H2O)

f) Ca(NO3)2(aq) + (NH4)2CO3(aq) ----------------> CaCO3(s) + 2NH4NO3(aq)

ikadub [295]3 years ago
3 0

Answer:

a) 2NaOH(aq) + CuSO4(aq) ----> Cu(OH)2(s) + Na2SO4(aq)

b) Ca(OH)2(aq) + CO2(g) --> CaCO3 + H2O (the chemical equation is already balanced as is)

c) Pb(NO3)2 + H2SO4 --> PbSO4 + 2HNO3

d) 2KNO3 --> 2KNO2 + O2

e) H2SO4 + 2(NaOH) --> Na2SO4 + 2(H2O)

f) Ca(NO3)2(aq) + (NH4)2CO3(aq) --> CaCO3(s) + 2NH4NO3(aq)

Explanation:

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In molecules, regions of electron density are usually found around the atom, and its bonds. In de-localized orconjugated systems, such as phenol,benzene and compounds such as hemoglobin and chlorophyll, the electron density covers an entire region, i.e., in benzene they are found above and below the planar ring. This is sometimes shown diagrammatically as a series of alternating single and double bonds. In the case of phenol and benzene, a circle inside a hexagon shows the de-localized nature of the compound.

5 0
3 years ago
What is the mass of bromine gas if it has a pressure of 720 mmHg, volume of 25mL and a temperature of 18.3 degrees Celsius
Annette [7]

Answer:

             Mass = 0.158 g

Explanation:

Formula used,

P V = n R T

Or,

n = P V / R T

Putting values,

n = 0.948 atm . 0.025 L / 0.0821 L.atm.K⁻¹.mol⁻¹ . 291.45

n = 0.00099 mol

Note: we have changed pressure from mmHg to atm, volume from mL to L and temperature from C to K)

Also,

Mass = n . Molecular Mass

Mass = 0.00099 mol × 159.808 g/mol

Mass = 0.158 g

7 0
2 years ago
Please help me I can’t figure it out
lukranit [14]
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8 0
3 years ago
Determine the compound type for the following formulas: C12H22011 Mg(OH)2 H20 Cu3Zn2 Au <br>​
Scorpion4ik [409]

Answer:

C12H22O11  

✔ covalent

Mg(OH)2    

✔ Ionic

H2O    

✔ covalent

Cu3Zn2    

✔ metallic

Au      

✔ metallic

Explanation:

7 0
3 years ago
Read 2 more answers
2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2
nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with H_2 to form CH_4 and H_2O. balanced reaction is:

CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

No. of moles of CO = 0.800 mol

No. of moles of H_2 = 2.40 mol

Volume = 8.00 L

Concentration = \frac{Moles}{Volume\ in\ L}

Concentration of CO = \frac{0.800}{8.00} = 0.100\ mol/L

Concentration of H_2 = \frac{2.40}{8.00} = 0.300\ mol/L

                 CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

Initial            0.100      0.300             0   0

equi.            0.100 -x    0.300 - 3x     x    x

It is given that,

at equilibrium H_2O (x) = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium H_2 = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium CH_4 = 0.0386 M

Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}

Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90

8 0
3 years ago
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