What is the molecular geometry of the left carbon atom (circled) in acetic acid? The left carbon atom is attached to three hydro
gen atoms and one carbon atom through single bonds. The right carbon atom is attached to a carbon atom and an oxygen atom through single bonds and a second oxygen atom through a double bond.
1 answer:
Answer: Tetrahedral geometry
Explanation: The structure of the acetic acid is shown in the image below.
The left carbon atom is the one which is attached to three hydrogen atoms through single bonds and to one carbon atom through single bond as well.
Thus the orbitals which are used in the process of the formation of the chemical bond between these 4 are sp3 orbitals. And these orbitals results in the formation of the tetrahedral geometry.
The right carbon atom that is attached to a carbon atom and an oxygen atom through single bonds and a second oxygen atom through a double bond has trigonal planar geometry which involves the sp2 orbitals for the formation of the bond.
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Answer: 0.20 M
Explanation:
According to the dilution law,
where,
= molarity of stock solution = 1.40 M
= volume of stock solution = 72.0 ml
= molarity of diluted solution = m
= volume of diluted solution = 248 ml
Now 124 mL portion of this prepared solution is diluted by adding 133 mL of water.
According to the dilution law,
where,
= molarity of stock solution = 0.41 M
= volume of stock solution = 124 ml
= molarity of diluted solution = m
= volume of diluted solution = (124 +133) ml = 257 ml
Thus the final concentration of the solution is 0.20 M.