Answer:
A and B
Explanation:
This is because there was emission of gamma (Y) radiations in both the reactions.
Answer is (3) both mass number and atomic number.
The notation is ₅₅¹³⁷Cs. The Cs represents the chemical symbol of Caesium element. The subscript number at the left hand side of the symbol indicates the atomic number. Hence, atomic number of Cs is 55. The superscript number at the left hand side of the symbol shows the mass number. Hence, the mass number of the Cs is 137.
The electron configuration of V³⁺ is [Ar]
. The ion is paramagnetic because it has two unpaired electrons
<h3>
What is paramagnetic?</h3>
- A weak magnetic field supplied externally can weakly attract some materials, which then create internal magnetic fields that are directed in the same direction as the applied magnetic field. This phenomenon is known as paramagnetic.
- Diamagnetic materials, in contrast, are attracted to magnetic fields and produce induced magnetic fields that are directed in the opposite direction from the applied magnetic field.
- The majority of chemical elements and some compounds are considered to be paramagnetic materials.
- Paramagnetic materials have a relative magnetic permeability that is somewhat more than 1, which makes them attracted to magnetic fields.
- The applied field induces a linearly decreasing magnetic moment that is relatively weak.
- Modern experiments on paramagnetic materials are frequently done with a sensitive analytical balance since it typically requires a sensitive analytical balance to identify the effect.
To learn more about paramagnetic with the given link
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They should identify the confounding variable.
Some condition that is not examined by the scientist might alter the experiment result. That condition is called confounding variable. If the method of the experiment same but result is very different, there should be unidentified confounding variable. It could be air humidity, temperature, ventilation, light, time of the year or anything that might not be seen by naked eye.
Try to redo the experiment with controlling variable as much as possible.
The half-life equation is written as:
An = Aoe^-kt
We use this equation for the solution. We do as follows:
5.5 = 176e^-k(165)
k = 0.02
<span>What is the half-life of the goo in minutes?
</span>
0.5 = e^-0.02t
t = 34.66 minutes <----HALF-LIFE
Find a formula for G(t) , the amount of goo remaining at time t.G(t)=?
G(t) = 176e^-0.02t
How many grams of goo will remain after 50 minutes?
G(t) = 176e^-0.02(50) = 64.75 g