Explanation:
The volume of given lead nitrate solution is:
52.5 mL.
The amount of lead iodide formed is ---0.248 g.
To get the molarity of lead (II) ion follow the below-shown procedure:
The number of moles of lead iodide formed is:

0.000537 mole of lead iodide contains --- 0.000537 moles of lead (II) ion.
Thus, the number of moles are there, volume is there, and to get the molarity of lead (II) ion use the formula:

Molarity of lead iodide is --- 0.0102 M.
The reaction produces 6 g of carbon dioxide.
The word equation is
methane + oxygen → carbon dioxide + water
12.2 g + 4 g → x g + 20 g
The <em>Law of Conservation of Mass</em> tells us the total mass of the reactants must equal the mass of the products. Then
12.2 g + 14 g =<em> x</em> g + 20 g
<em>x</em> = 12.2 + 14 – 20 = 6
The mass of carbon dioxide is 6 g.
<em>Note</em>: The answer can have <em>no decimal places</em> because you gave none for the masses of oxygen and water.
CdCl2+2NH4NO3
It is substitution reaction
Cd is metal with 2+ which connect with Cl(-)
NO3 with NH4 form salt
Answer:
35 amu
Explanation:
In an atom, only masses of protons and neutrons are relevant. electrons are so small in size that their masses are negligible.
The mass of 1 proton/neutron is 1amu.