Answer:
y = 130(24/13)^(x -10)
Step-by-step explanation:
The y-value changes by a factor of 240/130 = 24/13 for a unit change in the x-value. This means we can write the function as though it had an initial value of 130 and a growth factor of 24/13, translated 10 units to the right.
y = 130(24/13)^(x -10)
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<em>Additional comment</em>
This can also be written in the form ...
y = a·e^(kx)
where a=130·(24/13)^(-10) ≈ 0.28266, and k=ln(24/13) ≈ 0.61310
Isolate the x. Note the equal sign. What you do to one side, you do to the other. First, add 1/3y to both sides
8x - 1/3y (+1/3y) = 15 (+1/3y)
8x = 15 + 1/3y
Divide 8 from both sides
(8x)/8 = (15 + 1/3y)/8
x = 15/8 + 1/24y
x = 1/24y + 1.875
x = 1/24y + 1.875 is your answer
hope this helps
Answer:
60 + 70n ≤ 200
Step-by-step explanation:
Since the $200 is a maximum, only inequalities with "≤ 200" make any sense in this context.
Since the unit rate for training sessins is $70, only expressions containing 70n make any sense in this context.
The only inequaity that makes any sense in this context is ...
60 + 70n ≤ 200
Answer:
easy
Step-by-step explanation:
