Answer:
A: T = 120 N
B: T = 88.42 N
C: T = 70 N
Explanation:
Part A:
Since, the lighter bucket is supported by my had. So, the only unbalanced force in the system is the weight of heavier bucket. Hence, the tension in rope will be equal to the weight of heavier bucket.
<u>T = 120 N</u>
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Part B:
This is the case where, two masses hang vertically on both sides of the pulley. To find the tension in such case we have the formula:
T = (2 m₁m₂g)/(m₁+m₂)
where,
m₁ = mass of heavier object = W₁/g = (120 N)/(9.8 m/s²) = 12.24 kg
m₁ = mass of lighter object = W₂/g = (70 N)/(9.8 m/s²) = 7.14 kg
g = 9.8 m/s²
Therefore,
T = [(2)(12.24 kg)(7.14 kg)(9.8 m/s²)]/(12.24kg + 7.14 kg)
T = 1713.6 N.kg/19.38 kg
<u>T = 88.42 N</u>
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Part C:
Since, the heavier bucket is on ground. So, its weight is balanced by the normal reaction of the ground. The only unbalanced force in the system is the weight of lighter bucket. Hence, the tension in rope will be equal to the weight of lighter bucket.
<u>T = 70 N</u>
Your answer would be D- Knowledge of the environment.
I hope this helped... ;)
Explanation:
The x component of the resultant force is the sum of the x components of the individual forces.
Fₓ = 65.0 cos 30° − 20.0 sin 20° − 30.0
Fₓ = 19.5
The y component of the resultant force is the sum of the y components of the individual forces.
Fᵧ = 65.0 sin 30° − 20.0 cos 20°
Fᵧ = 13.7
The magnitude is found with Pythagorean theorem:
F² = Fₓ² + Fᵧ²
F² = (19.5)² + (13.7)²
F = 23.8
Reaction is the answer. If you're wondering why, all you need to do is look up the definitions of the words.