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Oksana_A [137]
3 years ago
9

Jimmy knows that to pass the fitness test he needs to be able to run 5 kilometers in 35 minutes. His pace monitor measures in mi

les. If he can run 3 miles in 35 minutes, will he pass his fitness test? Why or why not?
A) Yes, he will pass because he is running 5.2 km in 35 minutes.
B) Yes, he will pass because he is running 8.7 km in 35 minutes.
C) No, he will not pass because he is running 4.8 km in 35 minutes.
D) No, he will not pass because he is running 1.875 km in 35 minutes.
E) No, he will not pass because he is running 1.225 km in 35 minutes.
Business
2 answers:
Liula [17]3 years ago
8 0

Answer:

The answer is c

Explanation: just did it

slega [8]3 years ago
4 0

Answer:

The answer is option (c), no he will not pass because he is running 4.8 miles in 35 minutes

Explanation:

This can be expressed as;

Speed=Distance/Time

where;

Distance to be covered=5 kilometers

Time=35 minutes

replacing;

speed=(5/35)=0.143 km/min

In order to pass the fitness test his speed has to be greater than 0.143 km/min

Determine if 3 miles per 35 minutes is greater than 0.143 km/min

I mile=1.6 kilometers

How many kilometers make 3 miles,

Jimmy runs=(3×1.6)=4.8 kilometers in 35 minutes

Speed=4.8/35=0.137 kilometers/minute

Speed jimmy runs (0.137 km/min)<the pace he needs to run to pass fitness test(0.143 km/min)

The answer is option (c), no he will not pass because he is running 4.8 miles in 35 minutes

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Answer:

Following are the solution to this question:

Explanation:

Assume that r_1  will be a 12-month for the spot rate:

\to 1.25 \% \times \frac{100}{2} \times 0.99 + \frac{(1.25\% \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{100} \times \frac{100}{2} \times 0.99 + \frac{(\frac{1.25}{100} \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{2} \times 0.99 + \frac{(\frac{1.25}{2} +100)}{(1+\frac{r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 0.625 +100)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 100.625)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\

\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\\to 0.61875 -98 = \frac{402.5}{(2+r_1)^2}\\\\\to -97.38125= \frac{402.5}{(2+r_1)^2}\\\\\to (2+r_1)^2= \frac{402.5}{ -97.38125}\\\\\to (2+r_1)^2= -4.13\\\\ \to r_1=3.304\%

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\to \frac{1.5}{2}  \times 0.99+\frac{1.5}{2}\times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(\frac{1.5}{2} +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 0.7425+0.75 \times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(0.75  +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1+0.0165)^2}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1.033)}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\

\to 1.4925 \times 0.96+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328-97= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to -95.5672= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to (1+\frac{r_2}{2})^3= -1.054\\\\\to r_2=3.577\%

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\to 1.25\% \times \frac{100}{2} \times 0.99+1.25\% \times \frac{100}{2} \times \frac{1}{(1+\frac{3.300\%}{2})^2}+1.25\%\times\frac{100}{2} \times \frac{1}{(1+\frac{3.577\%}{2})^3}+(1.25\% \times \frac{\frac{100}{2}+100}{(1+\frac{r_3}{2})^4})=96\\\\

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The amount of cash received from the sale is calculated to be $336,300.

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