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forsale [732]
3 years ago
14

**URGENT, I WILL PAY 30 POINTS, PLEASE HELP**

Physics
2 answers:
kirill [66]3 years ago
7 0

The answer is <u>A</u>.

The wavelength is the length to each curve. Each answer choice has the same length of a box so we can count the amount of curves in each option.

Option A has 10 visible curves.

Option B has 3 visible curves.

Option C has 4 visible curves.

Since option A has the most curves, that means that it has the shortest wavelengths.

Best of Luck!

melamori03 [73]3 years ago
4 0

All three windows are the same size.

A has 10 complete waves visible through the window. B has 3, and C has 4.

So A must have the smallest wavelengths.

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As a marble rolls across the floor, it gradually slows to a stop due to friction. Which statement best describes the change in m
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Answer:

I belive it would be "C"

Explanation:

If it was any of the other answers "B" it would instantly stop. "A" it would roll forever.

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How does the direction of the electric current, moving across a battery powered device, differ from the direction of travel in t
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They both have different wave traction's
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A meter stick is balanced at the 50 cm mark. You tie a 20 N weight at the 20 cm mark. Where should a 30 N weight be placed so th
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Answer:

20 cm to the right of the center or 20+50 = 70 cm from the left side.

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The length of meter stick is 1 m = 100 cm

Balance point on 50 cm

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Torque is obtained when force is multiplied with the distance

As the force is conserved we have

\dfrac{20}{30}\times 30=20\ cm

The distance will be 20 cm to the right of the center or 20+50 = 70 cm from the left side.

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Initial velocity=3m/s, final velocity=5m/s, displacement=2m. Find the acceleration.
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alexandr1967 [171]

Answer:

v=\sqrt{k\frac{e^2}{m_e r}}, 2.18\cdot 10^6 m/s

Explanation:

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k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}

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e is the magnitude of the charge of the electron

e is the magnitude of the charge of the proton in the nucleus

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v=\sqrt{k\frac{e^2}{m_e r}}

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and the charge is

e=1.6\cdot 10^{-19} C

Substituting into the formula, we find

v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s

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