Consider the matrices. what are the dimensions of the project matrix of two of these matrices
1 answer:
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Answer:
A.
B. Perimeter = 190.6 yd
Step-by-step explanation:
A. Distance between P(10, 50) and R(80, 10):
(nearest tenth)
B. Distance around the park = Perimeter = PR + PQ + QR
PR = 80.6 yd
PQ = |50 - 10| = 40 yd
QR = |80 - 10| = 70 yd
Perimeter = 80.6 + 40 + 70
Perimeter = 190.6 yd
Answer:
Presumably you're solving for x here? Without further information we'll assume that.
With that in mind, x is approximately equal to 0.86 and -0.46
Step-by-step explanation:
Let's start by putting it in the usual ax² + bx + c format.
let's solve it. First we'll multiply both sides by five, making the first term a perfect square:
Now we'll add 11 to both sides:
Which makes the left side a perfect square:
And now we can solve for x:
Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.
That gives us two answers: