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topjm [15]
3 years ago
8

Scot has a 50 g sample of sandstone. The sandstone is formed by sedimentation, compaction, and cementation of 50-g of sand parti

cles. Based on this information, what can Scot conclude?
A) Mass is conserved in the rock cycle.
B) The structure of sand remains the same.
C) The sand retains its properties within sandstone
D) The volume of the parts is conserved in the rock cycle.
Chemistry
2 answers:
kupik [55]3 years ago
5 0

AAAAAAAAAAAAAAAYYYYYYEEEEE THE ANSWER IS A I GOT IT ON USATESTPREP

olya-2409 [2.1K]3 years ago
3 0
Since the mass stays the same, the mass is conserved in the rock cycle.
The answer is A.
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Occupational Safety and Health Administration has set the limit on the maximum percentage of carbon dioxide (CO2) in air a worke
Lyrx [107]

Answer:

The minimum rate of fresh air in the room is 176 moles/min

Explanation:

High exposure of CO₂ has health effects as headaches, increased heart rate, elevated blood pressure, coma, asphyxia, convulsions, etc.

0,500 mole% of CO₂ in air means 0,500 moles of CO₂ per 100 moles of air

As the rate of sublimation of CO₂ is 0,880, the minimum rate of fresh air in the room must be:

\frac{0,500 moles CO_{2}}{100 moles Air} = \frac{0,880 moles CO_{2}/min}{X}

X = <em>176 moles of Air/min</em>

<em></em>

I hope it helps!

4 0
3 years ago
The volume of gas occupied 240.0ml when the pressure is 1.20 atm what volume at constant pressure.will the gas occupies when the
Marizza181 [45]

Answer:

334.89 ml

Explanation:

V2 = V1P1/P2

V2 = 240×1.2/0.86

V2 = 334.89 ml

7 0
2 years ago
17.0 g of Cl_2 has a volume of 9.22 L at 17°C. What is its pressure?
TiliK225 [7]

Answer:

17.0 g of hask2 lahhwle 11c u2b8ss

7 0
3 years ago
The average speed of oxygen molecules in air is about ____. (1 point) 0 km/h 170 km/h 1700 km/h 17,000 km/h
LenKa [72]

The average speed is calculated using the following formulaspeed = \sqrt{\frac{3kT}{m} }


Where

k = 1.381 X  10^{-23} J / K

T = 298 K [room temperature]

m = mass of each molecule of oxygen

mass of one mole of oxygen molecules = 32 g / mol

mass of one molecule of oxygen will be = \frac{32}{6.023 X 10^{23} }

mass of one molecule of oxygen will be = 5.31 X 10^{-23} g = 5.31 X 10^{-26} kg

putting values

average speed = \sqrt{\frac{3 X 1.381 X  10^{-23} X 298}{5.31 X 10^{-26} kg} }

Average speed = 482.19 m / s

average speed = 1735.8 km / h

so approx = 1700 km/h

4 0
3 years ago
Read 2 more answers
H2SO4(aq)+LiOH(aq)→ Express your answer as a chemical equation. Identify all of the phases in your answer. Enter noreaction if t
kifflom [539]

Answer:

H₂SO₄ (aq) + 2LiOH (aq) ⇒ Li₂SO₄ (aq) + 2H₂O (l)

Explanation:

This is an acid-base reaction, so we know the products are going to a salt/ionic compound and water.

7 0
3 years ago
Read 2 more answers
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