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Alika [10]
3 years ago
8

Occupational Safety and Health Administration has set the limit on the maximum percentage of carbon dioxide (CO2) in air a worke

r can breathe at 0.500% by mole. If dry ice (solid CO2) is sublimating (becoming a gas) in a room at a rate of 0.880 mol/min, what is the minimum rate that fresh air has to be supplied to the room so that the concentration of CO2 in the room doesn't exceed 0.500% by mole? Assume the room is well mixed, and the volume of the solid dry ice does not change
Chemistry
1 answer:
Lyrx [107]3 years ago
4 0

Answer:

The minimum rate of fresh air in the room is 176 moles/min

Explanation:

High exposure of CO₂ has health effects as headaches, increased heart rate, elevated blood pressure, coma, asphyxia, convulsions, etc.

0,500 mole% of CO₂ in air means 0,500 moles of CO₂ per 100 moles of air

As the rate of sublimation of CO₂ is 0,880, the minimum rate of fresh air in the room must be:

\frac{0,500 moles CO_{2}}{100 moles Air} = \frac{0,880 moles CO_{2}/min}{X}

X = <em>176 moles of Air/min</em>

<em></em>

I hope it helps!

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What mass in grams would 5.7L of hydrogen gas occupy at STP?​
tekilochka [14]

Answer:  The correct answer is:  " 0.54 g " .

__________________________________________

Explanation:

Note that "hydrogen gas" is:  

H₂ (g)  ;   that is:  a "diatomic element" (diatomic gas) ;

_________________________________________

The molecular weight of "H" is:  1.00794 g ;

   (From the Periodic Table of Elements).

So, the molecular weight of:  H₂ (g)  is:

    " 1.00794 g * 2  = 2.01588 g ; {use calculator) ;

_________________________________________

Note the conversion for a gas at STP:

______

  1 mol of a gas = 22.4 L gas;

___

i.e. " 1 mol / 22.4 L " ;

____

So:     " 5.7 L H₂ (g)  *  \frac{1 mol H_{2} }{22.4 L} *\frac{2.01588 g}{mol} =? ;

The "L" ("literes" cancel out to "1" ;  since "L/L = 1 ;

The "mol" (moles) cancel out to "1" ; since "mol/mol = 1 ;

____

and we are left with:

____

 [5.7 * 2.104588 g ] / 22.4  =  ?  g ;

______________________

→ [ 11.9961516  g ] / 22.4 =

          0.53554248214  g ;l

_____________________________

We round this value to:  " 0.54 g " ;

 → since "5.7 L " has 2 (two) significant figures;  

     22.4 is an exact number conversion;

     and "5.7 L" has fewer significant figures than:

    " 2.104588 " ; or:  " 1.00794 " .

  → as such: We round to "2 (two) significant figures."

______________________________

Hope this is helpful.  Wishing you the best in your academic endeavors!

_______________________________

8 0
2 years ago
4. How many moles are in 54.0 grams of Silver?
sineoko [7]
4. Molar mass of silver m Ms~=108 g/mol
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5. 6.3*(108/1)=680.4g

6. Avogadro's number : Na~=6.022×10^23<span>. </span>
6.0*(6.022*10^23/1)=36.132*10^23 atoms

7. Molar mass of Krypton : Mk=84 g/mol
112/84=1.33 moles of Kr

8. 1.93*10^24*(1/(6.022×10^23))=3.2 moles KF

9. Molar mass of Silicon : Ms=28 g/mol
86.2*(1/28)*(6.022×10^23/1)=18.5*10^23 atoms of silicon

10. Molar mass of Magnesium : M1=24 g/mol
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7 0
3 years ago
How many molecules are in one mole of a compound?
valentina_108 [34]

Answer:6.022 x 10^23 molecules

Explanation: Since one mole of any chemical compound always contains 6.022 x 10^23 molecules, you can calculate the number of molecules of any substance if you know its mass and its chemical formula.

3 0
3 years ago
Describe use of H₂S an analytical reagent?<br><br>​
Gemiola [76]

Answer:

The main use for hydrogen sulfide is in the production of sulfuric acid and elemental sulfur. ... H2S is used to prepare the inorganic sulfides you need to make those products. As a reagent and intermediate, hydrogen sulfide is beneficial because it can prepare other types of reduced sulfur compounds.

7 0
3 years ago
How many moles of calcium nitrate would react with 4.55 moles of chromium(iii) sulfate to produce calcium sulfate and chromium(i
Rasek [7]
The equation for the reaction between the calcium nitrate and chromium sulfate to form calcium sulfate and chromium(iii) nitrate is,
                            3Ca(NO3)2 + Cr2(SO4)3 --> 3CaSO4 + 2Cr(NO3)3
The balanced equation shows that for every 1 mole of chromium sulfate, there will be 3 moles of calcium nitrate. Therefore for this item, there will be 4.55 moles times 3 which is equal to 13.65. 
6 0
3 years ago
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