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Alika [10]
3 years ago
8

Occupational Safety and Health Administration has set the limit on the maximum percentage of carbon dioxide (CO2) in air a worke

r can breathe at 0.500% by mole. If dry ice (solid CO2) is sublimating (becoming a gas) in a room at a rate of 0.880 mol/min, what is the minimum rate that fresh air has to be supplied to the room so that the concentration of CO2 in the room doesn't exceed 0.500% by mole? Assume the room is well mixed, and the volume of the solid dry ice does not change
Chemistry
1 answer:
Lyrx [107]3 years ago
4 0

Answer:

The minimum rate of fresh air in the room is 176 moles/min

Explanation:

High exposure of CO₂ has health effects as headaches, increased heart rate, elevated blood pressure, coma, asphyxia, convulsions, etc.

0,500 mole% of CO₂ in air means 0,500 moles of CO₂ per 100 moles of air

As the rate of sublimation of CO₂ is 0,880, the minimum rate of fresh air in the room must be:

\frac{0,500 moles CO_{2}}{100 moles Air} = \frac{0,880 moles CO_{2}/min}{X}

X = <em>176 moles of Air/min</em>

<em></em>

I hope it helps!

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The reaction;
O(g) +O2(g)→O3(g), ΔH = sum of bond enthalpy of reactants-sum of food enthalpy of products.
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