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shutvik [7]
3 years ago
13

The average speed of oxygen molecules in air is about ____. (1 point) 0 km/h 170 km/h 1700 km/h 17,000 km/h

Chemistry
2 answers:
LenKa [72]3 years ago
4 0

The average speed is calculated using the following formulaspeed = \sqrt{\frac{3kT}{m} }


Where

k = 1.381 X  10^{-23} J / K

T = 298 K [room temperature]

m = mass of each molecule of oxygen

mass of one mole of oxygen molecules = 32 g / mol

mass of one molecule of oxygen will be = \frac{32}{6.023 X 10^{23} }

mass of one molecule of oxygen will be = 5.31 X 10^{-23} g = 5.31 X 10^{-26} kg

putting values

average speed = \sqrt{\frac{3 X 1.381 X  10^{-23} X 298}{5.31 X 10^{-26} kg} }

Average speed = 482.19 m / s

average speed = 1735.8 km / h

so approx = 1700 km/h

emmainna [20.7K]3 years ago
3 0

The answer to your question is 1700 km/h

I hope this helps

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Answer:
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Solution:
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For initial and final states of a gas the equation is,

                                           P₁ / T₁  =  P₂ / T₂
Solving for P₂,
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Data Given;
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                   T₁  =  27 °C + 273  =  300 K
 
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Putting values in eq. 1,

                                           P₂  =  (3 atm × 350 K) ÷ 300 K

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7 0
3 years ago
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nataly862011 [7]
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3 years ago
Write a net ionic equation that describes a slightly basic solution resulting from dissolving nac2h3o2 in water. Identify all of
Natali [406]

Answer: The net ionic equation will be as follows.

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Explanation:

The chemical equation for the given reaction is as follows.

      CH_{3}COONa(aq) + H_{2}O(l) \rightleftarrow CH_{3}COOH(aq) + NaOH(aq)

We know that a strong acid or base will dissociate completely into a solvent whereas a weak acid or base dissociates partially into the solvent. Hence, the ionic equation will be as follows.  

CH_{3}COO^{-}(aq) + Na^{+}(aq) H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + Na^{+}(aq) + OH^{-}(aq) Now, we will cancel the spectator ions from the above equation. Therefore, the net ionic equation will be as follows.

     CH_{3}COO^{-}(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + OH^{-}(aq)

or,  C_{2}H_{3}O^{-}_{2}(aq) + H_{2}O(l) \rightleftharpoons HC_{2}H_{3}O_{2}(aq) + OH^{-}(aq)

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7 0
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also it is to 2 sigfigs because we know that we go by the least number of sigfigs. hope this helped!

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