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shutvik [7]
3 years ago
13

The average speed of oxygen molecules in air is about ____. (1 point) 0 km/h 170 km/h 1700 km/h 17,000 km/h

Chemistry
2 answers:
LenKa [72]3 years ago
4 0

The average speed is calculated using the following formulaspeed = \sqrt{\frac{3kT}{m} }


Where

k = 1.381 X  10^{-23} J / K

T = 298 K [room temperature]

m = mass of each molecule of oxygen

mass of one mole of oxygen molecules = 32 g / mol

mass of one molecule of oxygen will be = \frac{32}{6.023 X 10^{23} }

mass of one molecule of oxygen will be = 5.31 X 10^{-23} g = 5.31 X 10^{-26} kg

putting values

average speed = \sqrt{\frac{3 X 1.381 X  10^{-23} X 298}{5.31 X 10^{-26} kg} }

Average speed = 482.19 m / s

average speed = 1735.8 km / h

so approx = 1700 km/h

emmainna [20.7K]3 years ago
3 0

The answer to your question is 1700 km/h

I hope this helps

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Answer:

An atom with 1 valence electron and an atom with 7 valence electrons

Explanation:

Covalent bond:

It is formed by the sharing of electron pair between bonded atoms.  

The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.

the number of valance electrons of oxygen are six and hydrogen is one that's why two hydrogen atoms are attached with one oxygen atom and complete the octet.

4 0
3 years ago
Question 8<br>Which one of the following salts does not contain water of crystallisation?​
BlackZzzverrR [31]
Baking soda is sodium bicarbonate in anhydrous form without any water of crystallisation and it is widely used as dry fire extinguisher because of its alkali nature.
7 0
2 years ago
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22.00 g of CO2 has a volume of 50.00 L and a pressure of 0.8210 atm. What must be the
creativ13 [48]

Answer:

T = 9.875K

Explanation:

The ideal gas Law is PV = nRT.

P = Pressure

V = Volume

n = amount of substance

R =  8.314 J/(K. mol)

T = Temperature in Kelvin

22g CO2

CO2 Molar Mass = 44g/mol

C = 12g/mol

O = 16g/mol

P = 0.8210atm

V = 50L

PV = nRT

0.8210 x 50 = 8.314 x 0.5 x T

41.05 =  4.157T

T = 41.05/4.157

T = 9.875K

3 0
3 years ago
When 4.50 L of hydrogen gas react with an excess of nitrogen gas at standard temperature and pressure, how many liters of ammoni
VARVARA [1.3K]

Answer:

           3.0 L of NH₃

Solution:

The equation is as follow,

                                    N₂  +  3 H₂     →       2 NH₃

According to equation,

          67.2 L (3 mole) H₂ at STP produces  =  44.8 L (3 mole) of NH₃

So,

                            4.50 L of H₂ will produce  =  X L of NH₃

Solving for X,

                     X  =  (4.50 L × 44.8 L) ÷ 67.2 L

                     X  =  3.0 L of NH₃

5 0
3 years ago
While conducting a lab experiment, Ali calculated that 1.20 E6 Joules of heat were needed to melt 18.5 kilograms of an unknown s
nordsb [41]

Answer:

Latent heat of fusion of the substance is 6.49\times 10^{4}J/kg

Explanation:

Latent heat of fusion denotes amount of energy (heat) per unit mass required to melt a solid material at constant temperature and pressure i.e. at it's melting point

Here amount of heat required = 1.20\times 10^{6}J

Mass of unknown substance being melted = 18.5 kg

So, latent heat of fusion of the substance = (required heat energy to melt)/(mass of the unknown substance) = \frac{1.20\times 10^{6}}{18.5}J/kg=6.49\times 10^{4}J/kg

So, latent heat of fusion of the substance is 6.49\times 10^{4}J/kg

7 0
3 years ago
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