Answer:
A would be the lowest, then C, and B would be the highest.
Explanation:
Elements tend to become more reactive as you move down the periodic table. This happens because the atoms become progressively larger and lose their hold on the outer eletrons more easily.
Answer:
= 1.0593 g
Explanation:
1.1% NaCl by mass, means;
1.1 g per 100 g = 0.011
Therefore; the amount of NaCl present in 93.6 g of the solution is;
= 0.011 × 96.3 g
<u>= 1.0593 g</u>
Answer:
D
Explanation:
bs I just done that on my work and asked my teacher if it was right she said it was
Answer:
0.147 billion years = 147.35 million years.
Explanation:
- It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
- Half-life time is the time needed for the reactants to be in its half concentration.
- If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
- Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
- The half-life of Potassium-40 is 1.25 billion years.
- For, first order reactions:
<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>
Where, k is the rate constant of the reaction.
t1/2 is the half-life of the reaction.
∴ k =0.693/(t1/2) = 0.693/(1.25 billion years) = 0.8 billion year⁻¹.
- Also, we have the integral law of first order reaction:
<em>kt = ln([A₀]/[A]),</em>
<em></em>
where, k is the rate constant of the reaction (k = 0.8 billion year⁻¹).
t is the time of the reaction (t = ??? year).
[A₀] is the initial concentration of (Potassium-40) ([A₀] = 100%).
[A] is the remaining concentration of (Potassium-40) ([A] = 88.88%).
- At the time needed to be determined:
<em>8 times as many potassium-40 atoms as argon-40 atoms. Assume the argon-40 only comes from radioactive decay.</em>
- If we start with 100% Potassium-40:
∴ The remaining concentration of Potassium-40 ([A] = 88.88%).
and that of argon-40 produced from potassium-40 decayed = 11.11%.
- That the ratio of (remaining Potassium-40) to (argon-40 produced from potassium-40 decayed) is (8: 1).
∴ t = (1/k) ln([A₀]/[A]) = (1/0.8 billion year⁻¹) ln(100%/88.88%) = 0.147 billion years = 147.35 million years.
It will take the Ne gas approximately 1.2 s to equilibrate between the two sides.
We know that the time taken for a gas to diffuse is dependent on the molar mass of the gas. This is one of the interpretations of Graham's law of diffusion in gases. Thus, Let;
t1 = time taken for Rn to equilibrate = 4.0 s
t2 = time taken for Ne to equilibrate = ?
M1 = molar mass of Rn = 222g/mol
M2 = molar mass of Ne = 20 g/mol
Using
t1/t2 = √M1/M2
4/t2 = √222/20
4/t2 = 3.33
t2 = 4/3.33
t2 = 1.2 seconds
Learn more about diffusion in gases: brainly.com/question/879602
