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3 years ago

6

How does a balenced chemical equation satisfy the Law of Conservation of Mass?

1 answer:

defon3 years ago

7 0

The answer is A. In a chemical reaction matter can't be created or destroyed, so a balanced equation shows this. Hope this helps

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We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to

andreyandreev [35.5K]

<u>Answer:</u> The correct answer is Option 5.

<u>Explanation:</u>

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

$M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of the NaOH.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of the $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL$

Putting all the values in above equation, we get:

$M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M$

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base.

We are given:

$n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL$

Putting values in above equation, we get:

$1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M$

Hence, the correct answer is Option 5.

7 0

3 years ago

How many atoms does C₆H₄Cl₂ have?

Charra [1.4K]

Answer:

There are 12 atoms in the compound

6 0

3 years ago

If the mass of an object is 10 kg and the acceleration of an object due to

mars1129 [50]

Hmm the answer is 2.454

No explanation needed it’s just 2.454

5 0

3 years ago

A solution with a pH = 13 has approximately how many moles of OH– ions per liter?

GuDViN [60]

Answer :

(A) The number of moles of $OH^-$ ions per liter is, 0.1 moles/L

(B) The number of molecules of $H^+$ ion is, $6.022\times 10^{10}$

(C) The pH of the solution will be, 4

<u>Solution for part A :</u>

First we have to calculate the pOH of the solution.

As we know that,

$pH+pOH=14\\\\13+pOH=14\\\\pOH=1$

Now we have to calculate the moles of $OH^-$ ion per liter.

$pOH=-\log [OH^-]\\\\1=-\log [OH^-]$

$[OH^-]=0.1moles/L$

<u>Solution for part B :</u>

First we have to calculate the $H^+$ ion concentration.

$pH=-\log [H^+]\\\\13=-\log [H^+]$

$[H^+]=10^{-13}moles/L$

Now we have to calculate the number of molecules of $H^+$ ion

As, 1 mole contains $6.022\times 10^{23}$ number of molecules of $H^+$ ion

So, $10^{-13}$ moles contains $6.022\times 10^{23}\times 10^{-13}=6.022\times 10^{10}$ number of molecules of $H^+$ ion

<u>Solution for part C :</u>

$pH=-\log [H^+]\\\\pH=-\log (1\times 10^{-4})$

$pH=4$

6 0

4 years ago

Read 2 more answers

At a constant temperature, a sample of helium at 760 torr in a closed container was compressed from 5.0 L to 3.0 L. What was the

borishaifa [10]

Answer:

The new pressure exerted by the He, is 1266.6 Torr

Explanation:

A typical problem of gases where the volume is increased and the moles and T° keeps on constant. This is an indirect proportion because when the volume of the flask is increased, pressue decreases because molecules collide to a lesser extent with the walls of the vessel.

P₁ . V₁ = P₂ . V₂

760 Torr . 5L = P₂ . 3L

P₂ = (760 Torr . 5L) / 3L

P₂ = 1266.6 Torr

7 0

3 years ago