Redox reactions consist of reduction and oxidation reactions
oxidation reactions are the giving out of electrons, the oxidation number of the species giving out the electrons increases during oxidation
reduction reactions are taking in electrons and the oxidation number of the species taking in electrons reduces after reduction
in the reaction Ca + Cl₂ --> CaCl₂
oxidation numbers of Ca in Ca - 0 and CaCl₂ - +2
oxidation numbers of Cl in Cl₂ - 0 and CaCl₂ - -1
oxidation number of Ca has increased from 0 to +2 therefore Ca is oxidised
Answer:
Molarity NaOH = 0.85M (2 sig figs)
Explanation:
48.0ml(0.220M H₂SO₄) + 25ml(Xmolar NaOH)H₂SO₄ + 2NaOH => Na₂SO₄ + 2H₂O
2(molarity x volume) H₂SO₄ = (molarity x volume) NaOH
2(0.220M x 48.0ml) = 25.0ml x Molarity NaOH
Molarity NaOH = 2(0.220M x 48.0ml)/25.0ml = 0.8448M ≅ 0.85M (2 sig figs)
Answer:
1.39 Atoms
Explanation:
When converting from moles to atoms, multiply the number of moles by Avogadro's number
Multiply 2.30 moles by Avogadro's number (6.022*10^23)
= 1.3851 Atoms
=1.39 Atoms (sigfig)
The name of the sub-atomic particles in the nucleus of atom are protons and neutrons
Hope it helps you!!!!
