Answer:
q = 38,5 kJ
Explanation:
In its melting point, at 0°C, water is liquid. The boiling point of water is 100°C. It is possible to estimate the heat you required to raise the temperature of water from 0°C to 100°C using:
q = C×m×ΔT
Where C is specific heat of water (4,184J/g°C), m is mass of water (92,0g) and ΔT is change in temperature (100°C-0°C = 100°C)
Replacing:
q = 4,184J/g°C×92,0g×100°C
q = 38493 J, in kilojoules:
<em>q = 38,5 kJ</em>
<em></em>
I hope it helps!
Answer:
Acid: HCl(aq), conjugate base: Cl⁻(aq)
Base: CO₃⁻²(aq), conjugate acid: HCO₃⁻(aq)
The rewrite reaction is shown below.
Explanation:
The acid compound is the one that loses an H⁺, and the compound formed when it happens is its conjugate base. The base compound is the acceptor of H⁺, and its conjugate acid is the compound formed (Brosted-Lowry theory).
So, the acid-base pairs are:
Acid: HCl(aq), conjugate base: Cl⁻(aq)
Base: CO₃⁻²(aq), conjugate acid: HCO₃⁻(aq)
The TUMS® is an antacid, so it intends to reduce the concentration of the strong acid HCl. So, the forward reaction is favored. It can be represented with the forward arrow larger than the reversible arrow, as shown in the image below.
Extensive properties depend on the amount of substance. The volume of a sample is an extensive property: 1000 grams of water takes up more volume than 10 grams of water. Mass is also an extensive property.
Answer:
3441.6 grams.
Explanation:
2 O₃ → 3 O₂
First we <u>convert 71.7 moles of ozone (O₃) into moles of oxygen gas (O₂)</u>, using the <em>stoichiometric coefficients</em> of the reation:
71.7 mol O₃ *
= 107.55 mol O₂
Then we <u>convert 107.55 moles of O₂ into grams</u>, using the <em>molar mass of O₂</em>:
107.55 mol * 32 g/mol = 3441.6 g