Answer:
V = 331.59m/s
Explanation:
First we need to calculate the time taken for the shell fire to hit the ground using the equation of motion.
S = ut + 1/2at²
Given height of the cliff S = 80m
initial velocity u = 0m/s²
a = g = 9.81m/s²
Substitute
80 = 0+1/2(9.81)t²
80 = 4.905t²
t² = 80/4.905
t² = 16.31
t = √16.31
t = 4.04s
Next is to get the vertical velocity
Vy = u + gt
Vy = 0+(9.81)(4.04)
Vy = 39.6324
Also calculate the horizontal velocity
Vx = 1330/4.04
Vx = 329.21m/s
Find the magnitude of the velocity to calculate speed of the shell as it hits the ground.
V² = Vx²+Vy²
V² = 329.21²+39.63²
V² = 329.21²+39.63²
V² = 108,379.2241+1,570.5369
V² = 109,949.761
V = √ 109,949.761
V = 331.59m/s
Hence the speed of the shell as it hits the ground is 331.59m/s
Answer: C
<span>
The Smith System is one of
the earliest forms of space management that was invented by Harold Smith. <span> He </span>established the Smith
System Driver Improvement Institute to help prevent collisions caused by bad
driving habits. The earliest strategies of Smith system includes the following:
aim high in steering, keep your eyes moving, get the big picture, make sure
others see you and leave yourself an out where you can escape
from your current path of travel when potential mistakes on the road happen.</span>
Answer:
Explanation:
We know that impedance of a RLC circuit is given by 
So 
here R is resistance 
is inductive reactance and 
is capacitive reactance
To minimize the impedance 
should be zero we know that 
So 
We know that 
So 
Where f is resonance frequency
The answer is C) Surface runoff.
