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storchak [24]
2 years ago
11

Record two activities where you would expect to have a steep learning curve, two where you would have an “average” learning curv

e, and two where you would expect to see a shallow learning curve. Reflect on your results. Do you think that this graph would look the same for everyone?
Physics
1 answer:
lora16 [44]2 years ago
3 0

Answer:

r

Explanation:

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A voltage of 220V (rms) line to netralvoltage is applied across a three phase Y connected resistive load. Each phase of the Y co
mrs_skeptik [129]

Answer:

Current through each phase Vp = 2.2A

Total three phase power Pt= 1.45kW

Power factor of the load pf = 1

Explanation:

i) Find current through each phase

Vp =220V (rms)

Z =100 Ω

I = Vp/Z

 = 220/100

 = 2.2A

ii) Find the total three phase power

for a resistive load, Power, P = VI

Power for each phase is given as:

P = 220 * 2.2

  = 484 W

Total power TP =3* P

                          =484*3

                          = 1452W

                           =1.45kW

 iii) Find the power factor of the load

Phase angle for a resistive load is 0.

α= 0

Hence, power factor of load = cos α

                                          pf      = cos 0

                                             pf    = 1

5 0
3 years ago
Which electromagnet will produce the strongest magnetic force? (1 point)
Contact [7]

Answer:

Y

Explanation:

Y will produce the strongest magnetic force because the current intensity is medium and it has 50 turns in the wire. the number of turns will increase the force because the magnetic field will be more concentrated.

Have a great day :)

7 0
3 years ago
Read 2 more answers
A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber
Tasya [4]

Answer:

Explanation:

Calculate the volume of the lead

V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}

Now calculate the bouyant force acting on the lead

F_L = Vpg

F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N

This force will act in upward direction

Gravitational force on the lead due to its mass  will act in downward direction

Hence the difference of this two force

T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N

If V is the volume submerged in the water then bouyant force on the bobber is

F_B=V'pg

Equate bouyant force with the tension and gravitational force

F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}

Now Total volume of bobble is

\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\

=\large\boxed{4.52 \%}

7 0
3 years ago
A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration to a velocity of 13 m/s. What is the magn
olga55 [171]

Answer:

The acceleration is a = 2.75 [m/s^2]

Explanation:

In order to solve this problem we must use kinematics equations.

v_{f} = v_{i} + a*t\\

where:

Vf = final velocity = 13 [m/s]

Vi = initial velocity = 2 [m/s]

a = acceleration [m/s^2]

t = time = 4 [s]

Now replacing:

13 = 2 + (4*a)

(13 - 2) = 4*a

a = 2.75 [m/s^2]

5 0
3 years ago
The diagram shows the apparent motion of the Sun across the sky. EAST WEST Sunrise Which action causes the Sun to appear to move
Andreas93 [3]
C. West to east is the correct answer
8 0
3 years ago
Read 2 more answers
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