1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
krok68 [10]
3 years ago
8

A shell is fired with a horizontal velocity in the positive x direction from the top of an 80 m high cliff. The shell strikes th

e ground 1330 m from the base of the cliff. What is the speed of the shell as it hits the ground
Physics
1 answer:
Sonbull [250]3 years ago
7 0

Answer:

V = 331.59m/s

Explanation:

First we need to calculate the time taken for the shell fire to hit the ground using the equation of motion.

S = ut + 1/2at²

Given height of the cliff S = 80m

initial velocity u = 0m/s²

a = g = 9.81m/s²

Substitute

80 = 0+1/2(9.81)t²

80 = 4.905t²

t² = 80/4.905

t² = 16.31

t = √16.31

t = 4.04s

Next is to get the vertical velocity

Vy = u + gt

Vy = 0+(9.81)(4.04)

Vy = 39.6324

Also calculate the horizontal velocity

Vx = 1330/4.04

Vx = 329.21m/s

Find the magnitude of the velocity to calculate speed of the shell as it hits the ground.

V² = Vx²+Vy²

V² = 329.21²+39.63²

V² = 329.21²+39.63²

V² = 108,379.2241+1,570.5369

V² = 109,949.761

V = √ 109,949.761

V = 331.59m/s

Hence the speed of the shell as it hits the ground is 331.59m/s

You might be interested in
A small block with a mass of 0.0600 kg is attached to a cord passing through a hole in a frictionless, horizontal surface (Figur
pogonyaev

Answer with Explanation:

We are given that mass of block=0.0600 kg

Initial speed of block=0.63 m/s

Distance of block  from the hole when the block is revolved=0.47 m

Final speed=3.29 m/s

Distance of block  from the hole when the block is revolved=9\times 10^{-2}m

a.We have to find the tension in the cord in the original situation when the block has speed =v_0=0.63 m/s

T=\frac{mv^2}{r}

Because tension is equal to centripetal force

Substitute the values

T=\frac{0.06\times (0.63)^2}{0.47}=0.05 N

b.v=3.29 m/s

T=\frac{mv^2}{r}=\frac{0.06\times (3.29)^2}{0.09}=7.2 N

c.Work don=Final K.E-Initial K.E

W=\frac{1}{2}m(v^2-v^2_0)

W=\frac{1}{2}(0.06)((3.29)^2-(0.63)^2)

W=0.31 J

4 0
3 years ago
Read 2 more answers
A truck on the freeway originally moving at 6.6 meters/second accelerates uniformly with acceleration a = 2.8 meters/second2 for
Sonja [21]

Answer:

139.514 metres

Explanation:

Initial velocity of the truck = 6.6 m/s

Acceleration of the truck = 2.8 m/s^2

Time interval = 7.9 s

Therefore we use the formula,

s = ut + 1/2 at^2

*where s(the distance travelled)...u(the initial velocity)...t(the time period)

; s = 6.6(7.9) + 1/2 (2.8)(7.9)^2

; s = 52.14 + 87.374

The distance moved by the truck = 139.514m

8 0
3 years ago
What is one standard kilogramun si system<br><br><br><br><br>​
Phoenix [80]

Answer:

The kilogram (kg) is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015 ×10−34 when expressed in the unit J s, which is equal to kg m2 s−1, where the meter and the second are defined in terms of c and ∆νCs.

3 0
3 years ago
Read 2 more answers
Extend your thinking: household appliances are usually connected in a parallel circuit. why do you think it might be a problem i
alexandr1967 [171]
The equivalent resistance of several devices connected in parallel is given by
\frac{1}{R_{eq}} =  \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n}
where R_i are the resistances of the various devices. We can see that every time we add a new device in parallel, the term \frac{1}{R_{eq}} increases, therefore the equivalent resistance of the circuit R_{eq} decreases.

But Ohm's law:
I= \frac{V}{R_{eq}}
tells us that if the equivalent resistance decreases, the total current in the circuit increases. The power dissipated through the circuit (and so, the heat produced) depends on the square of the current:
P=I^2 R
therefore if there are too many devices connected in parallel, this can be a problem because there could be too much power dissipated (and too much heat) through the circuit.
6 0
3 years ago
A cube-shaped piece of copper has sides of 4cm each and it's density is
iris [78.8K]

Answer:

64 cm^3

Explanation:

<u>Density </u>

The density of a substance is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

\displaystyle \rho=\frac{m}{V}

We have a cube-shaped piece of copper of 4 cm of side length. The volume of the piece is:

V=(4\ cm)^3=64\ cm^3

Surprisingly, no other magnitude is required, thus the answer is:

\mathbf{64 cm^3}

5 0
2 years ago
Other questions:
  • What would happen if there were no action-reaction forces in effect and you tried walking down a sidewalk
    11·1 answer
  • An air compressor compresses 15 L/s of air at 120 kPa and 20°C to 800 kPa and 300°C while consuming 6.2 kW of power. How much of
    7·1 answer
  • Power _____. A. is the rate of doing work B. is work times displacement C. is force times displacement D. depends only on the wo
    11·1 answer
  • A converging lens of focal length 20 cm is placed in contact with, and to the left of, a diverging lens of focal length 30 cm. I
    10·1 answer
  • How many pounds must a sandbag weigh to test if a safety net can absorb the proper amount of force
    10·2 answers
  • Technician A says that the ABS electrohydraulic unit can be bled using bleeder screws and the manual method. Technician B says t
    9·1 answer
  • A motorcycle starts at rest and accelerates at a rate of 3 meters per second squared (m/s2) over a time period of 5 seconds (s).
    15·1 answer
  • (4)science who ever gets this right will get a brainlest
    5·2 answers
  • Why does diamond sparkles stars twinkles?​
    8·1 answer
  • *please refer to photo attached* The figure below shows a small, charged sphere, with a charge of q = +44.0 nC, that moves a dis
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!