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stich3 [128]
3 years ago
11

How do you do 1? Please help me step by step or send a picture of your work

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0
Subtract 6 from -4, to make -10, then divide both sides by ten, making -x=-2, then subtract both to make x=2
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Which of the following is not a way to represent the solution of the inequality 3(2x − 1) greater than or equal to 4(2x − 3) − 3
vfiekz [6]
3(2x - 1) > = 4(2x - 3) - 3
6x - 3 > = 8x - 12 - 3
6x - 3 > = 8x - 15
6x - 8x > = -15 + 3
-2x > = -12
x < = -12/-2
x < = 6


the incorrect one is : A number line with a closed circle on 6, shading to the right


3 0
3 years ago
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Combine the following expressions. Help pleaseeeeeeeeeeeeeeeeeee
spin [16.1K]

Answer:

it's the third one

4 0
4 years ago
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Please help me with this - its about percent changes
Serhud [2]

Answer:

110.06

Step-by-step explanation:

Make a ratio: 95.20 / x = 86.5 / 100   (86.5 = 100% - 13.5%)

Cross multiply: 95.20 x 100 = 86.5x

9520 = 86.5x

110.06 = x

6 0
2 years ago
Need Help With Math. One Question
alina1380 [7]

Answer: 2 < x < 16

The triangle inequality theorem says that if we have a triangle with sides a,b,c then

b-a < c < b+a

with b being longer than 'a'

In this case, a = 7 and b = 9 and c = x

so we have

b-a < c < b+a

9-7 < c < 9+7 .... replace a with 7, replace b with 9

2 < c < 16

2 < x < 16 .... replace c with x

So x can be any number between 2 and 16. The value of x cannot be equal to 2. Also, x cannot be equal to 16 either.

8 0
4 years ago
Encuentra el cociente ??​
vagabundo [1.1K]

For this case we must find the quotient of the following expression:

\frac {(- 8x ^ 2 * y) (- 7x ^ 5 * y ^ 3)} {- 2x ^ 2 * y ^ 3}

We can rewrite the expression as:

(We take into account that- * - = +)

\frac {56x ^ 2 * y * x ^ 5 * y ^ 3} {- 2x ^ 2 * y ^ 3} =

By definition of multiplication of powers of the same base, we place the same base and add the exponents:

\frac {56x ^ {2 + 5} * y ^ {1 + 3}} {- 2x ^ 2 * y ^ 3} =\\\frac {56x ^ {7} * y ^ {4}} {- 2x ^ 2 * y ^ 3} =

By definition of division of powers of the same base, we place the same base and subtract the exponents:

-28x^{ 7-2} * y^{ 4-3} =\\-28x ^ 5 * y

Answer:

-28x ^ 5 * y

4 0
3 years ago
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