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mixer [17]
3 years ago
14

If 4.35 grams of zinc metal react with 35.8 grams of silver nitrate, how many grams of silver metal can be formed and how many g

rams of the excess reactant will be left over when the reaction is complete? Show all of your work. unbalanced equation: Zn + AgNO3 yields Zn(NO3)2 + Ag
Chemistry
1 answer:
vaieri [72.5K]3 years ago
5 0
The balanced chemical reaction is written as:

<span>Zn + 2AgNO3 = Zn(NO3)2 + 2Ag

To determine the grams of silver metal that is being produced, it is important to first determine which is the limiting reactant and the excess reactant from the given initial amounts. We do as follows:

4.35 g Zn ( 1 mol / 65.38 g ) ( 2 mol AgNO3 / 1 mol Zn ) = 0.1331 mol AgNO3 needed
35.8 g AgNO3 ( 1 mol / 169.87 g ) ( 1 mol Zn / 2 mol AgNO3 ) = 0.1054 mol Zn needed

Therefore, the limiting reactant would be the zinc metal since it would be consumed completely in the reaction. The excess amount of AgNO3 would be:

0.2107 mol AgNO3 - 0.1331 mol AgNO3 = 0.0776 mol AgNO3 left ( 169.87 g / 1 mol ) = 13.19 g AgNO3 left

0.0665 mol Zn ( 2 mol Ag / 1 mol Zn) ( 107.9 g / 1 mol) = 14.3581 g Ag produced</span>
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I need help fast...........
guapka [62]

Answer:

I think its might be 1 because the ionic numbers for CA is +2 and for P its +3

8 0
2 years ago
An empty beaker weighs 25.91 g. When completely filled with water, the beaker and its contents have a total mass of 333.85 g. Wh
Finger [1]

Answer:

The beaker holds 307.94  mL

Explanation:

As we know that the volume that beaker hold is the volume of water that occupied by it.

For this first we have to find mass of the water in the beaker

This can be calculated by the subtraction of beaker's weight from the weight of beaker and water.

     weight of water (m) = total weight - weight of beaker

Empty weight of beaker = 25.91 g

Weight of beaker with water = 333.85 g

Weight of water = 333.85 - 25.91 = 307.94 g

Density of water = 1 g/mL

We have

      Mass = Volume x density

      307.94  = Volume x 1

      Volume = 307.94  mL

The beaker holds 307.94  mL

3 0
3 years ago
Please help ill give you points and brainliest please ​
Paul [167]

Answer:

Answers with detail are given below

Explanation:

1) Given data:

Mass of Rb₃Rn = 76.19 g

Number of moles = ?

Solution:

Number of moles = mass/molar mass

Molar mass = 478.43 g/mol

Number of moles = 76.19 g/ 478.43 g/mol

Number of moles = 0.16 mol

2) Given data:

Mass of FrBi₂ = 120.02 g

Number of moles = ?

Solution:

Number of moles = mass/molar mass

Molar mass = 640.96 g/mol

Number of moles = 120.02 g/640.96 g/mol

Number of moles = 0.19 mol

3) Given data:

Mass of Zn₂F₃ = 88.24 g

Number of moles = ?

Solution:

Number of moles = mass/molar mass

Molar mass = 187.73 g/mol

Number of moles = 88.24 g/ 187.73 g/mol

Number of moles = 0.47 mol

4) Given data:

Number of moles of Sb₄Cl = 1.20 mol

Mass of Sb₄Cl = ?

Solution:

Number of moles = mass/molar mass

Molar mass = 522.49 g/mol

Mass = Number of moles × molar mass

Mass = 1.20 mol ×  522.49 g/mol

Mass = 626.99 g

3 0
3 years ago
Besides the concentration of the acid and its conjugate base, what else does one need to calculate the ph of a weak acid
Marta_Voda [28]
K_{a}, the acid disassociation constant. 
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3 years ago
Which of the following is a chemical property? a
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4 0
2 years ago
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