All categories

2 years ago

Which type of molecule is shown below?

Chemistry

1 answer:

otez555 [7]2 years ago

8 0

Answer:

D. Cyclic alkane

Explanation: there is no double or triple bond

You might be interested in

A student drops some metal paper clips in a box of sand. The student uses a magnet to separate the metal paper clips from the sa

Dmitriy789 [7]

Answer:

compound

Explanation:

because now there are one together

3 0

2 years ago

Consider 2H2 + O2 → 2H2O. To produce 1.2 g water, how many grams of H2 are required? Report to the correct number of significant

Elden [556K]

Answer:

0.133 mol (corrected to 3 sig.fig)

Explanation:

Take the atomic mass of H=1.0, and O=16.0,

no. of moles = mass / molar mass

so no. of moles of H2O produced = 1.2 / (1.0x2+16.0)

= 0.0666666 mol

From the equation, the mole ratio of H2:H2O = 2:2 = 1:1,

meaning every 1 mole of H2 reacted gives out 1 mole of water.

So, the no, of moles of H2 required should equal to the no, of moles of H2O produced, which is also 0.0666666 moles.

mass = no. of moles x molar mass

hence,

mass of H2 required = 0.066666666 x (1.0x2)

= 0.133 mol (corrected to 3 sig.fig)

3 0

2 years ago

What happens when an atom of sulfur combines with two atoms of chlorine to produce SCI2?

Aloiza [94]

Answer:..A.) Each chlorine atom shares a pair of electrons with the sulfur atom

3 0

1 year ago

The following reaction is exothermic. C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g)C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g) Predict the effect (shi

Zigmanuir [339]

Answer:

According to Le Chatelier's principle, increasing the reaction temperature of an exothermic reaction causes a shift to the left and decreasing the reaction temperature causes a shift to the right.

Explanation:

C6H12O6(s) + 6O2(g) ⇌6CO2(g) + 6H2O(g)

We are told that the forward reaction is exothermic, meaning heat is removed from the reacting substance to the surroundings.

According to Le Chatelier's principle,

1. for an exothermic reaction, on increasing the temperature, there is a shift in equilibrium to the left and formation of the product is favoured.

2. if the temperature of the system is decreased, the equilibrium shifts to right and the formation of the reactants is favoured.

3. if the reaction temperature is kept constant, the system is at equilibrium and there is no shift to the right nor to the left.

6 0

2 years ago

Read 2 more answers

For the following reaction, 22.0 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas . nitrogen mono

mash [69]

NO is the limiting reagent and 4.34 g is the amount of the excess reagent that remains after the reaction is complete

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called as limiting reagent.

The reaction:

$2NO(g) +2H_2(g)$ → $N_2 +2H_2O$

Moles of nitrogen monoxide

Molecular weight: $M_(_N_O_)$ =30g/mol

$n_(_N_O_) =\frac{mass}{molar \;mass}$

$n_(_N_O_) =\frac{22.0}{30g/mol}$

$n_(_N_O_) = 0.73 mol$

Moles of hydrogen

Molecular weight: $M_(_H_2_)$ =30g/mol

$n_(_H_2_) =\frac{mass}{molar \;mass}$

$n_(_H_2_) =\frac{5.80g}{2g/mol}$

$n_(_H_2_) = 2.9 mol$

Hydrogen gas is in excess.

NO is the limiting reagent.

The amount of the excess reagent remains after the reaction is complete.

$n_(_N_2_) =$ (2.9 mol- 0.73 mol NO x $\frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}$ ) x $\frac{2g \;of \;H_2}{mole \;of \;H_2}$

$n_(_N_2_) =$ 4.34 g

Learn more about limiting reagents here:

brainly.com/question/26905271

#SPJ1

5 0

1 year ago