About 46.1 pounds of apple would be needed per day of the trip.
I managed to extract the complete scenario from the attached image.
The trip is made up of 4 men and 3 women, making a total of 7 people.
Everyone has become accustomed to 1500 calories per day.
The total calories needed per day for 7 persons = 1500 x 7
= 10,500 calories
189 g of apple has only 95 calories, what g of apple will produce 10,500 calories?
= 10,500 x 189/95 = 20,889.67 g of apple
From conversion:
1 g = 0.00220462 pounds
20,889.67 g = 20,889.67 x 0.00220462
= 46.1 pounds of apple
More about dimensional analysis can be found here: brainly.com/question/22015862
The answer is C) Orbits the Nucleus
To find the moles, you can use the following formula
moles= Molarity x Liters
Molarity= 2.0 M
Liters= 0.0010 Liters ---------------->>>>>>>>>> 1.0 mL= 0.0010 Liters
moles= 2.0 M x 0.0010 Liters= 0.0020 moles
Answer:
3.64g
Explanation:
Given parameters:
Mass of NH₃ = 18.1g
Mass of Cu₂O = 90.4g
Unknown:
Limiting reactant = ?
Mass of N₂ formed = ?
Solution:
The reaction equation is given as:
Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O
The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species;
Number of moles = 
Molar mass of Cu₂O = 2(63.6) + 16 = 143.2g/mol
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
Number of moles of Cu₂O = 
= 0.13moles
Number of moles of NH₃ = 
= 5.32moles
From this reaction;
1 mole of Cu₂O combines with 2 mole of NH₃
So 0.13moles of Cu₂O will combine with 0.13 x 2 mole of NH₃
= 0.26moles of NH₃
Therefore, Cu₂O is the limiting reactant. Ammonia is in excess;
Mass of N₂;
Mass = number of moles x molar mass
1 mole of Cu₂O will produce 1 mole of N₂
0.13 mole of Cu₂O will produce 0.13 mole of N₂
Mass = 0.13 x (2 x 14) = 3.64g
