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3 years ago

7

Water flows through a cylindrical pipe of varying cross-section. The velocity is 3.0 m/s at a point where the pipe diameter is 1

.0 cm. What is the flow rate R

1 answer:

Setler79 [48]3 years ago

8 0

Answer:

The flow rate is $R =2.357 *10^{-4} \ m^3/s$

Explanation:

From the question we are told that

The velocity is $v = 3.0 \ m/s$

The diameter of the pipe is $d = 1.0 \ cm = 0.01 \ m$

The radius of the pipe is mathematically represented as

$r = \frac{d}{2}$

substituting values

$r = \frac{0.01}{2}$

$r = 0.005 \ m$

The flow rate is mathematically represented as

$R = v * A$

Where is the cross-sectional area of the pipe which is mathematically evaluated as

$A = \pi r^2$

substituting values

$A = 3.142 * (0.005)^2$

$A = 7.855 * 10^{-5} \ m^2$

So

$R = 3.0 * 7.855 *10^{-5}$

$R = 2.357*10^{-4} \ m^3 /s$

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