Question

Water flows through a cylindrical pipe of varying cross-section. The velocity is 3.0 m/s at a point where the pipe diameter is 1.0 cm. What is the flow rate R

Answer 1

Answer:

The flow rate is  $R =2.357 *10^{-4} \ m^3/s$

Explanation:

From the question we are told that

    The velocity is $v = 3.0 \ m/s$

   The  diameter of the pipe is  $d = 1.0 \ cm = 0.01 \ m$

 

The  radius of the pipe is mathematically represented as

            $r = \frac{d}{2}$

substituting values

            $r = \frac{0.01}{2}$

           $r = 0.005 \ m$

The flow rate is mathematically represented as

       $R = v * A$

Where is the cross-sectional area of the pipe which is mathematically evaluated as

      $A = \pi r^2$

substituting values

      $A = 3.142 * (0.005)^2$

     $A = 7.855 * 10^{-5} \ m^2$

So

    $R = 3.0 * 7.855 *10^{-5}$

    $R = 2.357*10^{-4} \ m^3 /s$