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krok68 [10]
3 years ago
5

The time that an object takes to complete its orbit once around the sun

Physics
1 answer:
Naya [18.7K]3 years ago
4 0

The farther away an object is from the Sun the slower it orbits around it. The closer an object is from the Sun the faster it orbits around it.

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How do you calculate acceleration
Eduardwww [97]

Answer: acceleration is equal to the change in velocity per unit time in seconds.

a= ∆v / t = vf - vi / t

Explanation: change in velocity or ∆v can be expressed as (vf - vi)

7 0
3 years ago
A child with a mass of 23 kg rides a bike with a mass of 5.5 kg at a velocity of 4.5 m/s to the south. Compare the momentum of t
serg [7]

Answer:

Explanation:

Given the following data;

Mass of child = 23 kg

Mass of bike = 5.5 kg

Velocity = 4.5 m/s

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

To find the momentum of each of them;

I. Momentum of the child

Momentum C = mass * velocity

Momentum C = 23 * 4.5

Momentum C = 103.5 Kgm/s

II. Momentum of the bike

Momentum B = mass * velocity

Momentum B = 5.5 * 4.5

Momentum B = 24.75 Kgm/s

Hence, we can deduce from the calculations that the momentum of the child is greater than that of the bike because of the higher mass possessed by the child.

4 0
2 years ago
The unit light-year is a measure of
stiv31 [10]
A light-year is a unit of distance.

The definition of a light-year is the distance light travels in one year.
5 0
3 years ago
Read 2 more answers
Which statement best defines an electric field?
dalvyx [7]
A region around a charged partical or object. Let me know if this works. Hope I could help you.
7 0
3 years ago
figure 2 shows a charged ball of mass m = 1.0 g and charage q = -24*10^-8 c suspended by massless string in the presence of a un
Vlad [161]

Answer:

E = 307667  N/C

Explanation:

Since the object's mass is 1 g, then its weight in newtons is 0.001 * 9.8 = 0.0098 N.

This weight should have the same magnitude of the vertical component of the tension T of the string (T * cos(37)) so we can find the magnitude of the tension T via:

0.0098 N = T * cos(37)

then T = 0.0098/cos(37) N = 0.01227 N

Knowing the tension's magnitude, we can find its horizontal component:

T * sin(37) = 0.007384 N

and now we can obtain the value of the electric field since we know the charge of the ball to be: -2.4 * 10^(-8) C:

0.007384 N = E * 2.4 * 10^(-8) C

Then  E = 0.007384/2.4 * 10^(-8)  N/C

E = 307667  N/C

8 0
3 years ago
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