Let u = initial vertical velocity.
Assume that
g = 9.81 m/s²,
Wind resistance is ignored.
When t = 0.220 s, the height is h = 0.537 m. Therefore
0.537 m = (u m/s)*(0.220 s) - (1/2)*(9.81 m/s²)*(0.220 s)²
0.537 = 0.22u - 0.2372
u = 3.519 m/s
The upward velocity after 0.220 s is
v = 3.519 - 9.81*0.22 = 1.363 m/s
At maximum height, the upward velocity is zero. The maximum height, H, is given by
(3.519 m/s)² - 2*(9.81 m/s²)*(H m) = 0
12.3834 - 19.6H = 0
H = 0.632 m
It goes higher by 0.632 - 0.537 = 0.095 m
Answers:
(a) The initial speed is 3.519 m/s.
(b) The speed at 0.537 m height is 1.363 m/s.
(c) It goes higher by 0.095 m.
Answer:
1) I believe The mass of a football player is important because. If you are a football player and you are not able to tackle ,push , throw the ball very far- exedra, then you will not be able to play because football includes many factors of weigh. therefor you have to have a greater mass or you will not be able to play football or you wont be very good which can lead to being kicked off the team. So in order to be able to play football you must be of a certain topic of weight.
Explanation:
.
Do not forget that mass = <span>volume x density
</span>Mass of 1 cm^3 = Density[/tex]

Then eventually we can find <span>mass of 5 cm^3 : =
</span>

So the answer is D
<span>And that's it. I'm sure it will help.</span>
Step 1: Identify the variables. ...Step 2: Determine the variable range. ...Step 3: Determine the scale of the graph. ...Step 4: Number and label each axis and title the graph.Step 5: Determine the data points and plot on the graph. ...Step 6: Draw the graph.